replacing blank values in a single column cell array with the previous value

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basically i have a list of values in a cell array.
A =
'-2.0372681e-10'
'0'
'-1.1641532e-10'
'-2.910383e-11'
'&nbsp'
'&nbsp'
'-1.45579e-11'
'0'
'&nbsp'
'2.9103759e-11'
'&nbsp'
'1.455188e-11'
'-2.910383e-11'
'7.2759396e-11'
'-1.45579e-11'
'2.9103759e-11'
'-4.3655746e-11'
'8.7311276e-11'
I want all the blanks to be filled with whatever the previous cell value is

Risposta accettata

Andy
Andy il 19 Mag 2011
Pending the answer to Sean de's comment, I will assume the first entry is not blank:
for ix=2:length(A)
if isempty(A{ix})
A{ix} = A{ix-1};
end
end
EDIT: As per Sean de's suggestion, the for loop now starts at 2. Michael, you may have to adjust this if the first element is allowed to be blank. (The code will not cause an error, but the result will not be what you intended.)

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