How to cluster 1D array so that approximately equal values are replaced by their average?

I have a 1D array that features "double-counts". I would like to consolidate or cluster the dataset in a way that replaces the double-counts with the average of the two double-counted values. Here's a sample dataset

xx=[185.0712  185.0715  185.5117  186.1008  186.5077  187.1303  187.5037  188.1596  188.1597  188.4993  189.1890  189.4949  190.2185  190.4903  191.2477  191.2480].'

Here's a screenshot where I've circled the relevant entries that are double counts:

Does anyone know how to do this?

Answer 1

[Walter Roberson]

https://www.mathworks.com/help/matlab/ref/uniquetol.html

[~, ~, G] = uniquetol(xx);
xxmean = grpstats(xx, G, 'mean');

[Travis Briles]

Thanks for your answer! However when I typed in exactly what you wrote, it throws an error.

close all
clear all
clc

xx=[185.0712  185.0715  185.5117  186.1008  186.5077  187.1303  187.5037  188.1596  188.1597  188.4993  189.1890  189.4949  190.2185  190.4903  191.2477  191.2480].'

[~, ~, G] = uniquetol(xx);
xxmean = grpstats(xx, G, 'mean');

This gives the error:

"Undefined function 'grpstats' for input arguments of type 'double'.

Error in Untitled7 (line 8)

xxmean = grpstats(xx, G, 'mean');"

Is grpstats part of some package or toolbox I need to download? Maybe part of the Statistics and Machine Learning Toolbox? https://www.mathworks.com/help/stats/index.html?s_tid=CRUX_lftnav

[Walter Roberson]

Statistics and Machine Learning Toolbox.

You can instead use

xx=[185.0712  185.0715  185.5117  186.1008  186.5077  187.1303  187.5037  188.1596  188.1597  188.4993  189.1890  189.4949  190.2185  190.4903  191.2477  191.2480].'

xx = 16×1

185.0712 185.0715 185.5117 186.1008 186.5077 187.1303 187.5037 188.1596 188.1597 188.4993

[~, ~, G] = uniquetol(xx, 1e-4);
xxmean = accumarray(G, xx, [], @mean)

xxmean = 13×1

185.0713 185.5117 186.1008 186.5077 187.1303 187.5037 188.1596 188.4993 189.1890 189.4949

[Travis Briles]

I downloaded the toolbox and now both solutions work. Thanks!