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Not enough input arguments

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ameen
ameen il 21 Giu 2013
Chiuso: MATLAB Answer Bot il 20 Ago 2021
i want to calculate rpm when two values approximately the same TT and T
this is the code
function rpm =zzzzzz(modelspeed,modelresistance,propellerdiameter,density,wakefraction,thrustdeduction)
va=modelspeed*(1-wakefraction);
for rpm=100:2000;
T=modelresistance/(1-thrustdeduction);
j=va/((rpm./60)*propellerdiameter);
kt=0.37159*(1-(j/0.955))^0.8;
TT=kt*density*(rpm./60)^2*propellerdiameter^4;
kq=0.0476*(1-(j/1.0064))^0.7;
q=kq*density*(rpm./60)^2*propellerdiameter^5;
if TT(rpm)/T>0.999 %when T~T’%
rpm
return
end
end
when i run this code i receive an error message ' Not enough input arguments.' for the line of this equation
va=modelspeed*(1-wakefraction);
Best Regards, Ameen
  2 Commenti
Angus
Angus il 21 Giu 2013
what are modelspeed and wakefraction?
Angus
Angus il 21 Giu 2013
really not sure if it could be causing any problems but I would encourage you to not use the name of your function as a variable inside the function. Rather
function rpm_calc = zzzzzz(...)
...
for rpm = 100:200;
...
if TT(rpm)/T>0.999
rpm_calc = rpm;
return
...
Not sure if using rpm inside the function is somehow trying to call the function again?

Risposte (2)

Azzi Abdelmalek
Azzi Abdelmalek il 21 Giu 2013
zzzzzz is not a script it's a function, and should be called like below
out=zzzzzz(modelspeed,modelresistance,propellerdiameter,density,wakefraction,thrustdeduction)
  5 Commenti
Azzi Abdelmalek
Azzi Abdelmalek il 21 Giu 2013
Is the error message the same?
ameen
ameen il 21 Giu 2013
yes

Matt Tearle
Matt Tearle il 21 Giu 2013
The error message you're getting seems to indicate a problem with how you're calling the function, rather than the function itself. I copied the function exactly as you have it, then did this:
>> zzzzzz(1,2,3,4,5,6)
And I got a different error message, related to line 10 ( if TT(rpm)/T>0.999 ).
Call the function just as I did. If you get the same error message as before, you might need to do
which zzzzzz
to figure out which function/variable MATLAB is actually finding (because it must be a different one).
Now, there are other issues with the function -- pay attention to the Code Analyzer messages you get in the Editor. I think this is what you're trying to do:
function rpm =zzzzzz(modelspeed,modelresistance,propellerdiameter,density,wakefraction,thrustdeduction)
va=modelspeed*(1-wakefraction);
for rpm=100:2000;
T=modelresistance/(1-thrustdeduction);
j=va/((rpm./60)*propellerdiameter);
kt=0.37159*(1-(j/0.955))^0.8;
TT=kt*density*(rpm./60)^2*propellerdiameter^4;
if TT/T>0.999 %when T~T’%
return
end
end
There are prettier ways to do it, but that should work.

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