How to convert cell to matrix

I have a cell which is given by A= 1x13cell. I want to extract the contents of the cell into the form of a matrix of size (13 x number of points each cell containd) is this possible? The number of points in each cell varies. Can you help me with this?

2 Commenti

I suggest you give a small example. For instance, if
C = {[1 2],[11 12 13]} % a cell array
how would you like the final matrix M to look like? Something like
1 2 NaN
11 12 13
?
yes, that's what I need

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Risposte (3)

Jan
Jan il 16 Lug 2013
Modificato: Jan il 16 Lug 2013
N = cellfun('length', C);
M = numel(C);
R = NaN(M, N);
for k = 1:M
R(1:N(k)) = C{k}; % Perhaps: reshape(C{k}, 1, [])
end

1 Commento

Ede gerlderlands
Ede gerlderlands il 16 Lug 2013
Modificato: Ede gerlderlands il 16 Lug 2013
Thank you for yor reply. But this gives me the whole nubers that are found in the cell in the decending order following rows. What I really want is the numbers per cell . That is 13 rows and what is found in them . Thank you

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David (degtusmc)
David (degtusmc) il 16 Lug 2013
Modificato: David (degtusmc) il 16 Lug 2013

2 voti

Look up cell2mat. The link for the documentation is below. I hope this helps

3 Commenti

I tried but didn't help me
Evan
Evan il 16 Lug 2013
This will only work for cells arrays containing matrices of constant size in each array.
That is true. I did not think about that. Thank you Evan.

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Jos (10584)
Jos (10584) il 17 Lug 2013
Modificato: Jos (10584) il 17 Lug 2013
Here is a suggestion
C = {[1 2 ;3 4],[11 12 13].',100:106} % a cell array
% make sure all elements are column vectors
C2 = cellfun(@(x) reshape(x,[],1), C,'un',0) ;
M = padcat(C2{:})

Richiesto:

il 16 Lug 2013

Commentato:

il 18 Lug 2018

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