convert complex number to Integers

I have a exponential function and cordic exponential function.

I see a differenc in output for exponential and cordic exp func

Example -

theta = [-pi:pi/4:pi]

y = exp(theta)

y1 = cordiccexp(theta)

cordic exponential works only for complex number where as exponential works for complex and real/integer numbers

Question - How to (Mathematics) get cordiccexp out same as exponetial function

Answer 1

[KSSV]

cordicexp calculates

cos(theta)+i*sin(theta)

To make cordicexp and exp same you need to use:

exp(i*theta)

Remember Euler's formula.

exp(i*x) = cos(x)+i*sin(x)

[Life is Wonderful]

Hi @KSSV

I tried as below but it seems i did not understand correctly. Please help me

theta = [-pi:pi/4:pi];
y = cos(theta)+i*sin(theta);
y1 = cordiccexp(y);
y2 = exp(i*theta);

figure;
subplot(2,1,1);plot(1:length(y),y1','r--','linewidth',2.5); hold on; grid on;legend('cordicexp');
subplot(2,1,2);plot(1:length(y),y2','b--','linewidth',2.5); hold on; grid on;legend('exponential');

I want cordiccexp output to work as exponential function output/ Not vice-versa

Thank you

[KSSV]

theta = -pi:pi/4:pi ; 
y1 = exp(1i*theta) ; 
y2 = cordiccexp(theta) ; 

figure;
hold on 
plot(1:length(y1),real(y1),'r','linewidth',2.5); 
plot(1:length(y2),real(y2),'*b','linewidth',2.5); 
grid on 
legend('exponential','cordicexp');

[Life is Wonderful]

I need below and not imaginary of cordic exponential.

theta = [-pi:pi/4:pi];
y = cos(theta)+i*sin(theta);
y1 = cordiccexp(theta);  % imaginary
y2 = exp(theta); % no imaginary

figure;
subplot(2,1,1);plot(1:length(y),real(y1),'r--','linewidth',2.5); hold on; grid on;legend('cordicexp');
subplot(2,1,2);plot(1:length(y),real(y2),'b--','linewidth',2.5); hold on; grid on;legend('exponential');