Extracting index of specified date from datetime array

168 visualizzazioni (ultimi 30 giorni)
Let us say that I have a datetime array which has dates that goes like these:
'2015-05-03 23:59:56'
'2015-05-03 23:59:56'
'2015-05-03 23:59:56'
'2015-05-03 23:59:56'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
Now, I would like to know the indices of one certain element, say {'2015-05-03 23:59:57'}. How can I get that?
I tried with example given in https://in.mathworks.com/help/finance/datefind.html, but even for the example given there is not getting executed in my pc. It is giving an error ‘Undefined function 'datefind' for input arguments of type 'double'.’. I suspect that it may be due to not having the proper toolbox. The toolbox that I am having are:
Curve Fitting Toolbox, Parallel Computing Toolbox, Partial Differential Equation Toolbox, Signal Processing Toolbox and Symbolic Math Toolbox
Thanks in advance.

Risposta accettata

Walter Roberson
Walter Roberson il 12 Mag 2021
S = datetime({'2015-05-03 23:59:56'
'2015-05-03 23:59:56'
'2015-05-03 23:59:56'
'2015-05-03 23:59:56'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'
'2015-05-03 23:59:57'})
S = 12×1 datetime array
03-May-2015 23:59:56 03-May-2015 23:59:56 03-May-2015 23:59:56 03-May-2015 23:59:56 03-May-2015 23:59:57 03-May-2015 23:59:57 03-May-2015 23:59:57 03-May-2015 23:59:57 03-May-2015 23:59:57 03-May-2015 23:59:57 03-May-2015 23:59:57 03-May-2015 23:59:57
probe = datetime('2015-05-03 23:59:57')
probe = datetime
03-May-2015 23:59:57
find(S == probe)
ans = 8×1
5 6 7 8 9 10 11 12
  3 Commenti
Stephen23
Stephen23 il 22 Mar 2023
@matteo franchi: it is clear that the date/time values do not exactly match each other. So you first need to decide if you want to find:
  • the single pair of closest date/time values?
  • all date/time values that are within a particular range/tolerance?
  • some other criteria...
Walter Roberson
Walter Roberson il 22 Mar 2023
Remember that when you use == that everything down to nanoseconds (or further) must be identical.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Mathematics in Help Center e File Exchange

Tag

Prodotti


Release

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by