Using index to name variables

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Lukas Netzer
Lukas Netzer il 12 Mag 2021
Commentato: Lukas Netzer il 13 Mag 2021
I'm running a script with a index containing:
t{1} = Location1;
t{2} = Location2;
t{3} = Location3;
tt{1} = "Location1";
tt{2} = "Location2";
tt{3} = "Location3";
t's are tables. Now the actual script does e.g. this:
for x = 1:1:size(t{n})
if t{n}.var1(x) == 0
a_tt{n}(x) = b_tt{n}(x) / t{n}.var2(x);
if t{n}.var2(x) == 0
a_tt{n}(x) = 0;
end
As can be seen above I am trying to get a_Location1 and b_Location2 - but it does not work that way. Is there a smooth way to get a_location1/2/3 and b_location1/2/3 using the index?
It's for a lot of lines in the script, so some way without doing it by hand, would be nice!
Thanks for your help!
  2 Commenti
Lukas Netzer
Lukas Netzer il 12 Mag 2021
one solution that would work is:
str1 = "a_" + tt{n};
str2 = "b_" + tt{n};
But as stated above, I have lots of those variables, is there maybe a better way?
Rik
Rik il 12 Mag 2021
Why do you want numbered variables? You shouldn't store data in a variable name.

Accedi per commentare.

Risposta accettata

Jan
Jan il 12 Mag 2021
Do not create variables names dynamically. This would store information in the names, where it is hard to access. Use the values of the variables instead.
You can use dynamic field names of structs:
a = struct()
for x = 1:1:size(t{n})
if t{n}.var1(x) == 0
a.(tt{n})(x) = b_tt{n}(x) / t{n}.var2(x);
elseif t{n}.var2(x) == 0
a.(tt{n})(x) = 0;
end
end

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