How does one use integral2 (double integral) symbolically?
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Mikayel
il 22 Ago 2013
Modificato: Walter Roberson
il 14 Mag 2024
I would like to get some help on how to use the integral2 symbolically?
E.g. I have a Joint PDF function -> "@(x,y) exp(-(x+y))"
To verify that it adds up to one, I did the following -> "integral2(pdf,0,inf,0,inf)" with the result being 1 as expected.
Now to calculate the Joint CDF symbolically I defined x and y as symbols and tried to do -> "cdf=@(u,v) exp(-(u+v))" and "integral2(cdf,0,x,0,y)". The error I got was -> "Error using integral2. XMAX must be a floating point scalar."
What I want to get is -> "(1-exp(-y))*(1-exp(-x))" !!
Your help will be much appreciated.
1 Commento
Dipak kumar Panigrahy
il 21 Mag 2020
clear
clc
syms rtstar
syms rt1 v delta R do %or assign numeric values to the variables
p=10;
cdf1=p*tan(delta)*R^2;
cdf2=p*tan(delta)*R^2;
eqn = ss == (int(int(cdf1,rt,rt1,rtstar),e,0,v)-int(int(cdf2,rt,rtstar,rt2),e,0,v));
sol = solve(eqn, rtstar)
can ayone tell me how to solve this eqn?
Risposta accettata
Shashank Prasanna
il 22 Ago 2013
From the documentation of integral2:
integral2
Numerically evaluate double integral
It is not meant for symbolic computation. If you are interested in symbolic results you need to have Symbolic Toolbox installed
Then you can use the int function:
3 Commenti
Shashank Prasanna
il 23 Ago 2013
Modificato: Shashank Prasanna
il 23 Ago 2013
Sir, you have to use functions from the Symbolic Toolbox.
>> syms u v
>> cdf = exp(-(u+v))
>> int(int(cdf,v,0,v),u,0,u)
Più risposte (1)
Okae
il 14 Mag 2024
Modificato: Walter Roberson
il 14 Mag 2024
how do i type j=\iint\of V_s\ [f\left(\varepsilon_{\left(\left(p+q\right)\right)}-f\left(\varepsilon_p\right)\delta\left(\varepsilon_{\left(\left(p+q\right)\right)}-\varepsilon_p-\hbar\omega q\right)\right]dp_{\left(x\right)d}p_y
in symbolic math toolbox?
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