Find does not work properly
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Riccardo Tronconi
il 16 Giu 2021
Commentato: Riccardo Tronconi
il 16 Giu 2021
Hi guys! I use the find command but it does not return what I expect.
for i=1:9:500
c=c+1;
d=find(Horizon{i:i+9,8} <= 2);
m=mean(Horizon{i:i+9,8});
report12{c,7}=m;
%if isnan(m)==0
%report12{c,1}=Horizon{i,1};
%report12{c,2}=Horizon{i+9,1};
end
For any value of i and then i+9 my d is always equal to: d= [1,2,3,4,5,6,7,8,9,10,11], of course if each value verifies the condition. What I really expect is filling d with the Horizon row index. let 's say:
d=find(Horizon{440:450,8} <= 2);
d=[440, 441,445,450] assuming only 4 values verifiy the condition
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Steven Lord
il 16 Giu 2021
Please provide a small sample of the Horizon variable from where you expected the find call to return data but it does not. My suspicion is that the elements in that section of Horizon display as 2 but the stored values are actually slightly larger than 2.
format % default display format
x = 2.000000001 % displays as 2
x <= 2 % but is not less than or equal to 2
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