Loop and Conditional Statements

1 visualizzazione (ultimi 30 giorni)
I've got two vectors 1x366 u and v, and I have to make a new 1x366 vector of the arctg of u and v.
But I've got a few conditions depending if the respective value of u and v are negative or positive.
Here's some of the code which I started writing, but I am stuck.
Thank you for any help.
for n = 1:length(u)
if u(n) <0 && v(n) < 0
atan(v./u);
elseif u(n) > 0 && v(n) < 0
atan(u./v) + 4.712;
elseif u(n) < 0 && v(n) > 0
atan(u./v) + 1.571;
elseif u(n) > 0 && v(n) > 0
atan(v./u) + 3.142;
end
end
  2 Commenti
Scott MacKenzie
Scott MacKenzie il 24 Giu 2021
Have you looked at atan2? This is the four-quadrant version of atan -- might be what you need.
Paulo Eduardo Beiral
Paulo Eduardo Beiral il 24 Giu 2021
Unfortunately atan2 wont help me in this case, I need exactly the atan with the conditions I entered in my code.
Thank you, mister.

Accedi per commentare.

Risposta accettata

Steven Lord
Steven Lord il 24 Giu 2021
As written your code calls atan at most once per element of u but then throws that result away. You also have magic numbers that look like approximations to multiples of pi.
Instead I recommend using logical indexing.
base1 = atan(v./u);
base2 = atan(u./v);
result = NaN(size(u)); % determine what you want result to be if none of the cases hold
case1 = (u < 0) & (v < 0);
result(case1) = base1(case1);
case2 = (u > 0) & (v < 0);
result(case2) = base2(case2) + (3*pi/2);
% and similar for case3 and case4

Più risposte (0)

Categorie

Scopri di più su Loops and Conditional Statements in Help Center e File Exchange

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by