Understanding fsolve() output when number of function evaluations is exceeded

Solving a nonlinear squared system of equations using fsolve(), in a simplified manner my code looks like this:

options = ('Display', 'iter', 'TolX', 1e-6, 'TolFun', 1e-6,...
	'MaxFunEvals',1e7,'MaxIter',1e7);
x1 = fsolve(@(x) num_ss_Al(x), x0, options)

Now, when the maximum number of function evaluations is reached (or the number of iterations) the variable "x1" actually gets assigned a non-zero complex part vector, i.e.:

x1 =
   1.0e+02 *
  Columns 1 through 9
   0.0214 + 0.0003i   0.0026 - 0.0000i   0.0100 + 0.0000i   0.1005 + 0.0000i   0.0004 - 0.0003i   0.0000 - 0.0001i  -0.0002 - 0.0000i   0.0026 + 0.0000i   0.6752 - 0.0000i
  Columns 10 through 18
   0.6720 - 0.0000i   0.0097 + 0.0005i   0.0028 - 0.0002i   0.0086 + 0.0003i   0.0000 - 0.0000i   0.0025 - 0.0001i   0.0006 + 0.0000i   0.0026 - 0.0002i   0.0020 + 0.0001i
  Columns 19 through 27
  -0.0010 + 0.0001i   0.0051 - 0.0001i  -0.0030 - 0.0001i   0.0001 - 0.0000i  -0.0028 - 0.0001i  -0.0045 - 0.0003i  -0.0104 - 0.0003i  -0.0048 + 0.0010i  -0.0030 + 0.0002i
  Columns 28 through 36
   0.0017 + 0.0001i  -0.0315 - 0.0038i   0.0100 - 0.0000i   0.0100 + 0.0000i   0.0100 + 0.0000i   0.0100 + 0.0000i   1.2980 - 0.0000i   0.0094 + 0.0000i   0.0096 + 0.0000i
  Columns 37 through 45
   0.0100 + 0.0000i   0.0100 + 0.0000i   0.0100 - 0.0000i   0.0107 - 0.0001i   0.0107 - 0.0001i   0.0185 - 0.0001i   0.0151 - 0.0000i   0.0273 - 0.0003i   0.0225 - 0.0001i
  Columns 46 through 54
   0.0191 - 0.0001i   0.0270 - 0.0004i   0.0081 + 0.0009i   0.0081 + 0.0009i  -0.0002 + 0.0000i  -0.0001 - 0.0000i   0.0094 + 0.0001i   0.0122 - 0.0013i   0.0106 - 0.0001i
  Columns 55 through 63
   0.0081 + 0.0009i   0.0003 - 0.0004i   0.0082 + 0.0001i   0.0089 - 0.0001i   0.0113 + 0.0006i   0.0005 - 0.0005i   0.0108 + 0.0006i   0.0096 + 0.0000i   0.0004 - 0.0003i
  Columns 64 through 68
   0.0001 - 0.0001i   0.0100 + 0.0000i   0.0135 + 0.0000i   0.0168 + 0.0000i   0.0136 - 0.0006i
   

What do those values correspond to given that the solver stopped prematurely? I thought first that they might be last iteration's evaluated values, but as far as I know and as stated in documentation the solution is a real vector or array, then for me it'd not be obvious why would numbers with non-zero imaginary part be evalutated. I'd appreciate some help in understanding this, thanks!