new array using average row of the old array
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I have an array M(1000,1000) and i want to build a new array N(1000,1000), where each element of N has the old value minus the average of its row (in M). If the element is zero no action will be taken. Also, from the average the zeros should be excluded.
Can you help me?
thank you in advance
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Azzi Abdelmalek
il 13 Ott 2013
Modificato: Azzi Abdelmalek
il 13 Ott 2013
Edit
out=bsxfun(@minus,M,mean(M,2)).*not(~M)
%or
idx=M==0;
out=bsxfun(@minus,M,mean(M,2));
out(idx)=0
6 Commenti
Azzi Abdelmalek
il 13 Ott 2013
Modificato: Azzi Abdelmalek
il 13 Ott 2013
Ok try this
idx=M==0;
moyenne=sum(M,2)./sum(not(~M),2)
out=bsxfun(@minus,M,moyenne)
out(idx)=0
Più risposte (1)
Andrei Bobrov
il 13 Ott 2013
ii = M == 0;
out = bsxfun(@minus,M,sum(M,2)./sum(~ii,2));
out(ii) = 0;
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