Azzera filtri
Azzera filtri

Bisection method not returning any values.

1 visualizzazione (ultimi 30 giorni)
David
David il 16 Ott 2013
Commentato: Matt J il 16 Ott 2013
So, I've written the following code for the bisection method, however it doesn't seem to be returning any values.
function [r, n] = bisection(a,b,f,tol)
if (f(a)*f(b) > 0)
error('Invalid choice of interval');
end
r = 0;
n = 0;
while ((b - a)/2 > tol)
n = n + 1;
r = (a + b)/2;
if(f(r) == 0)
break;
elseif (f(a)*f(b) < 0)
b = r;
else
a = r;
end
end
I'm using it with inputs of (0,1,q,0.5) I also tried tol as 0.1 too. q is some anonymous function that I defined, in this case it's q(x) = 3x - 1. Like, I type the command Bisection(0,1,q,0.5) and it executes without returning an error but doesn't return any numerical values whatsoever. Any ideas why this is?

Risposta accettata

Matt J
Matt J il 16 Ott 2013
Modificato: Matt J il 16 Ott 2013
Works fine for me. It returns the wrong value, but you can fix that by changing f(a)*f(b) < 0 to f(a)*f(r) < 0.
  5 Commenti
David
David il 16 Ott 2013
Actually, one further question. If I enter a quadratic equation, which may have 2 distinct roots,is there anyway to get it to output both roots? Or, would this be a much more complicated program.
Matt J
Matt J il 16 Ott 2013
Modificato: Matt J il 16 Ott 2013
No, there is no general algorithm for finding "all" roots of a general function without at least knowing in advance a lower bound on the spacing between the roots.
I assume, by the way, that this is just a homework exercise. In reality, you would never use your own home-brewed bisection algorithm. You would just use FZERO. So, there is no obvious rationale for giving this code more capabilities then the homework assignment requests.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Loops and Conditional Statements in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by