Splitting a string of numbers and '|'

[EDIT: Tue Jun 21 20:43:11 UTC 2011 - Reformat - MKF]
I cant find anything on the help for regexp that gives a way to split up numbers.
I have '1 | 2' and I need to get '1' and '2' as two separate strings.
I am getting this string from a listbox
Pos = get(handles.PositionList,'String')
Reg_num = get(handles.PositionList,'Value')
Reg_num is so that MATLAB knows which line is selected.

 Risposta accettata

Matt Fig
Matt Fig il 21 Giu 2011
str = '1 | 2';
S = regexp(str,'\d+','match')
Now S is a 1-by-2 cell array.
strcmp(S{1},'1')
strcmp(S{2},'2')

4 Commenti

Brittany
Brittany il 21 Giu 2011
yay! thank you
Brian
Brian il 24 Giu 2011
Is there a way to do this for mixed data strings?
str = '1 | 2|asdf| 123';
S = regexp(str,????)
strcmp(S{1},'1')
strcmp(S{2},'2')
strcmp(S{3},'asdf')
strcmp(S{4},' 123')
Brian
Brian il 24 Giu 2011
Jan Simon's method below works for mixed data strings.
See Jan's solution for that.

Accedi per commentare.

Più risposte (2)

Jan
Jan il 22 Giu 2011
Another solution:
strtrim(regexp('1 | 2', '\|', 'split'))
Pos = textscan(get(handles.PositionList,'String'), '%d', 'Delimiter', '|');
Pos{1}(get(handles.PostionList,'Value'))
Caution: If I recall correctly, I have seen cases where when you construct a listbox using '|' separated options, that the uicontrol internally converted this into a cell array of strings. It would therefore be more robust to check whether the 'String' returned was indeed ischar() or if it was iscell() instead.

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