It would be more elegant to define the solution for the 1x1 case as 1 rather than 0.
agree, but will leave as so, so as to not affect submitted solutions.
I disagree with the base case. A 1x1 matrix has 1 path. And, the empty matrix has no path (zero).
The first test case has been changed from 0 to 1 without rescoring past solutions.
The first test case is incorrect. The null path (starting and ending at the same place) is a solution. The 1x1 case should have 1 solution.
Flip the main diagonal of a matrix
Sum the 'edge' values of a matrix
Number of cyles and fixed points in a permutation
Method of Common Differences part-2
Game of Nim
nth Rational Number
Conjunctive Normal Form
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