Given the peak value of sine wave, calculate corresponding peak value of square wave, if both have same RMS voltage.
I think the answers in the test suite may be incorrect. Regardless, please make the test suite more robust.
I think the answers in your test suite are incorrect. If "peak value of a sine wave" (X) and "peak value of a square wave" (Y) are understood to be defined consistently, then (given equal RMS voltage) Y should be found as "X divided by sqrt(2)", not as "X multiplied by sqrt(2)".
Back to basics 3 - Temp Directory
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