Solution 122564

Submitted on 2 Aug 2012 by Santiago Velasco-Forero

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2 Comments

2 Comments

Peter Wittenberg on 11 Aug 2012

This is not two random rolls. The second number will never match the first, so the statistical distribution is not correct, although the test suite is not sophisticated enough to catch it.

Matthew M. on 28 Aug 2012

^Agreed.

Test Suite

Test	Status	Code Input and Output
1	Pass	%% x1 = zeros(1,6000); x2 = zeros(1,6000); for ii = 1:6000 [x1(ii),x2(ii)] = rollDice(); end numCt = sum( bsxfun( @eq, x1, (1:6)' ), 2 ) + sum( bsxfun( @eq, x2, (1:6)' ), 2 ); assert(all(round(numCt/200) == 10) && sum(numCt) == 12000)

Test

Status

Code Input and Output

Pass

%% x1 = zeros(1,6000); x2 = zeros(1,6000); for ii = 1:6000 [x1(ii),x2(ii)] = rollDice(); end numCt = sum( bsxfun( @eq, x1, (1:6)' ), 2 ) + sum( bsxfun( @eq, x2, (1:6)' ), 2 ); assert(all(round(numCt/200) == 10) && sum(numCt) == 12000)

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Problem 174. Roll the Dice!

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Problem 174. Roll the Dice!

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