Therefore, the second test is inappropriate
isequaln should be used.
The way the problem is written, all nonzero elements, including NaN, should be changed to 1, but the test case doesn't work this way.
I updated the second test with isequaln so that NaN == NaN is true.
It should be mentioned that 1 must be placed in the non-zero elements except for NaN.
Replace all nonzero numbers with 1. Leave any NaN elements as NaN.
Make a random, non-repeating vector.
Sum the numbers on the main diagonal
Compute Fibonacci Number
Side of an equilateral triangle
Angle difference between Hour Hand and Minute Hand of clock
LocateMembership | Membership of Matrix in another matrix
Sort the vector with the given index
Repeat The Components of Matrix
Look Up Mapping
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