given the 1x5 vector x, y must be the square of the horizontal concatenation of the third and fifth elements. So, if x = [1 1 1 1 1], y must be [1 1].
The example you give in the problem statement is not very demonstrative.
HAHAHAHA Matt: this was great!!!
Finding Perfect Squares
Which values occur exactly three times?
Sum all integers from 1 to 2^n
Calculate the area of a triangle between three points
Create sequnce 1 4 9 16 25.........
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