Problem 44947. Find the Oldest Person in a Room

Created by Pooja Lalan

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25035 Solutions
6921 Solvers

Last Solution submitted on Jun 21, 2021

Last 200 Solutions

Problem Comments

6 Comments

6 Comments

Show 3 older comments

Renato SL on 3 Sep 2019

In the first test suite, Robinson and Reed both have the same age, so I think either the test suite should be improved or Reed's age in the .mat file should be changed.

Anubhav Chaubey on 13 May 2020

Tricky question though

Sivaramarao B on 7 Jun 2020

Good one

rh x on 6 Apr 2021

function old_name = find_max_age(name,age)
[x,y]=max(age,[],2);
old_name=name(y);
end
who can help me,it ran incorrectly

Kulbhushan Chand on 9 May 2021

Interesting

Denise Anderson on 21 May 2021

rh x = I don't think you need the [] in your max matrix.

Solution Comments

Solution 5895165

1 Comment

1 Comment

Mouhamed Niasse on 4 Jun 2021 at 16:20

great

Solution 5834890

1 Comment

1 Comment

Shivam Gupta on 25 May 2021 at 15:51

This is a good question.

Solution 4847662

1 Comment

1 Comment

Md.Emtiajul Islam on 16 Feb 2021

simple indexing problem

Solution 4143880

1 Comment

1 Comment

Cory Cunningham on 11 Dec 2020

Tough problem

Solution 3832283

1 Comment

1 Comment

LIFE on 25 Nov 2020

its good

Solution 2649605

1 Comment

1 Comment

JOSE ANTONIO BUTENEGRO GARCIA on 3 Jul 2020

Keep in mind you have to obtain the position for the older person. This was taught in the max(var) class. Good luck!

Solution 2257445

2 Comments

2 Comments

VINAY SINNUR on 6 May 2020

tricky

SHIVANI CHORGE on 22 May 2020

fist find maximum age then use index of maximum age and by using that find corresponding name

Solution 2244218

1 Comment

1 Comment

srisai vangara on 29 Apr 2020

good one.

Solution 1937419

1 Comment

1 Comment

Omkar Chavan on 8 Apr 2020

Even typing only "Old_name = 2" resuts in size to be 13. What logic and language did you apply for getting size 8?

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function indexing

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Problem 44947. Find the Oldest Person in a Room

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Problem 44947. Find the Oldest Person in a Room

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