The results in the test suite seem to be based on the idea that the minimum and maximum areas are found by setting the third side to a3 = abs(a1-a2)+1 and a3=a1+a2-1, which is not correct. The correct maximum is somewhere in the middle. For example, in problem 2, the correct results are mn = 24.9987 and mx = 1250.0000.
yes.. i see that now.. my assumption was wrong.
Sorry for the misconception.
yet again we learn from our mistakes
Humm, I am certain that the minimum area of any triangle is zero, which corresponds to the degenerate case when one side is equal to the sum of the other two.
The maximum areas you report in the test cases are mostly wrong.
yes yes i see
thanks for pointing that out
Add two numbers
Is the input divisible by 3?
Area of rhombus
remove numbers from a string
find subscripts from linear index
How many ways?
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