Problem 487. Find perfect placement of non-rotating dominoes (easier)

list = [1 2
        4 3
        2 4

order = [1 3 2]

yields: [1 2][2 4][4 3]
    or: abs(2-2) + abs(4-4)
    or:        0 + 0
    or: 0

Solution Comments

Problem Recent Solvers383

Suggested Problems

• Check if sorted

  4493 Solvers

• Stuff the Board

  581 Solvers

• surrounded matrix

  1452 Solvers

• Create matrix of replicated elements

  397 Solvers

• String Array Basics, Part 1: Convert Cell Array to String Array; No Missing Values

  1967 Solvers

More from this Author51

• Make a simplified barcode

  178 Solvers

• Given a window, how many subsets of a vector sum positive

  871 Solvers

• Make a random, non-repeating vector.

  11215 Solvers

• Poker Series 02: isQuads

  89 Solvers

• Poker Series 07: IsTwoPair

  53 Solvers