Problem 60346. Classify numbers as abundant, deficient, or perfect
A number is perfect if the sum of its proper divisors (i.e., divisors excluding the number itself) is equal to itself. For example, 28 is perfect because 1+2+4+7+14 = 28. Cody Problems 1012, 2544, and 47458 deal with the perfect numbers.
If the sum of proper divisors is less than the number, it is called deficient, and if it is greater than the number, it is abundant. For example, 21 is deficient (1+3+7 = 11 < 21) and 24 is abundant (1+2+3+4+6+8+12 = 36).
Write a function to classify numbers as abundant, deficient, or perfect.
Solution Stats
Solution Comments
Show commentsProblem Recent Solvers8
Suggested Problems
-
How to find the position of an element in a vector without using the find function
2809 Solvers
-
172 Solvers
-
524 Solvers
-
Create a random logical vector of N elements of which M are true.
103 Solvers
-
I've got the power! (Inspired by Project Euler problem 29)
141 Solvers
More from this Author319
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!