I think test case 2 might be incorrect.
I disagree slightly with the expected solution to test 2.
Test 2 cos between [0 2pi]
[-pi/2 pi/2 3*pi/2]
I do not believe that -pi/2 is in the interval [0 2*pi].
If -pi/2 is desired then the answer to sin [0 2*pi] should be [-2*pi -pi 0 pi 2*pi]
Correction of assert function.
One of the ")" is in the wrong place.
assert(all(abs(find_zeros(@sin,0,2*pi) -[0 pi 2*pi]<1e-9)))
assert(all(abs(find_zeros(@sin,0,2*pi) -[0 pi 2*pi])<1e-9))
As mentioned by others, the 2nd test case is incorrect, -pi/2 is outside the interal [0,2*pi] for the function cosine. And if we do plot cos(x) on said interval, we notice that the cosine function crosses the x-axis only twice.
The –pi/2 has been removed from that test case.
Yeah, the test set is wrong...
Tune your guitar
Return the Fibonacci Sequence
Compute a dot product of two vectors x and y
Set some matrix elements to zero
Cody Computer Part 3 - Detect the graphic card used on Cody Computer
Remove the two elements next to NaN value
Unique values without using UNIQUE function
Combinations without using nchoosek
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