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Sebahattin Bektas


Ondokuz mayis university

Last seen: Today |  Attivo dal 2014

Followers: 0   Following: 0

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Professional Interests: Geodesy,Numerical Analysis,Optimization,Surface fitting

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  • 5-Star Galaxy Level 3
  • Personal Best Downloads Level 1
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Inviato


Cartesian Coordinate transformation (3D and 2D)
The function performs both reverse and direct problem-solving based on dual quaternions between two Cartesian coordinate systems...

23 giorni fa | 6 download |

Inviato


Intersection Arbitrary Ellipsoid and a Plane
This function computes the intersection any Ellipsoid and a Plane,

9 mesi fa | 4 download |

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Inviato


Spherical Triangle Solver
Spherical Triangle Solver This function solves any type of spherical triangle

oltre 2 anni fa | 2 download |

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Inviato


Least Square Coordinate Transformation in 2D
Cartesian Coordinate Transformation 2D Similarity,Affine,Projective

quasi 3 anni fa | 1 download |

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shortest_distance( X, axis )
The shortest distance(orthogonal distance) from a point to Ellipsoid or Hyperboloid

quasi 7 anni fa | 4 download |

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Converter Geodetic coordinates to Cartesian coordinates
Converter Geodetic coordinates to Cartesian coordinates on Triaxial,Biaxial ellipsoide or Sphere

oltre 8 anni fa | 4 download |

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Converter Cartesian coordinate to Geodetic coordinate
Converter Cartesian coordinates to Geodetic coordinates on Triaxial Ellipsoid or Biaxial Ellipsoid o

oltre 8 anni fa | 7 download |

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Conversion from conic parameters to geometric parameters of ellipsoids
Conic parameters to geometric parameters of ellipsoids.it checked real ellipsoid or not

circa 9 anni fa | 2 download |

Domanda


how do I extract conic equation from ellipsoid parameters
Hello I have a question how do I extract conic equation from ellipsoid parameters Here is ellipsoid parameters: the cen...

circa 9 anni fa | 2 risposte | 0

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risposte

Domanda


from the conic equation
given an equation A*x^2+B*y^2+C*z^2+ D*x*y + D*x*z + F*y*z -1=0 how do I extract the center [x0,y0,z0], the axes lengths [a,b...

quasi 10 anni fa | 1 risposta | 0

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