![photo](/responsive_image/150/150/0/0/0/cache/matlabcentral/profiles/19531346_1599993928247_DEF.jpg)
saja mk
Followers: 0 Following: 0
Statistica
RANK
18.152
of 292.726
REPUTAZIONE
2
CONTRIBUTI
7 Domande
2 Risposte
ACCETTAZIONE DELLE RISPOSTE
42.86%
VOTI RICEVUTI
1
RANK
of 147.893
CONTRIBUTI
0 Problemi
0 Soluzioni
PUNTEGGIO
0
NUMERO DI BADGE
0
CONTRIBUTI
0 Post
CONTRIBUTI
0 Pubblico Canali
VALUTAZIONE MEDIA
CONTRIBUTI
0 Punti principali
NUMERO MEDIO DI LIKE
Feeds
Domanda
values calculated from avector
s=[a b] how can calculate s1 and s2, if s1=exp(a)and s2=exp(b)?
quasi 4 anni fa | 1 risposta | 0
1
rispostaDomanda
transition probability matrix for markov
how to solve if the summation of each row in transition probability matrix in markov chain not equal to one?
quasi 4 anni fa | 1 risposta | 0
1
rispostaDomanda
Markov chain simulation code
In Markov chain code transition_probabilities = [0.1 0.9;0.8 0.2]; starting_value = 1; chain_length = 5; chain = zeros(1...
quasi 4 anni fa | 0 risposte | 0
0
rispostevalue in each iteration
but i get the optimal in GDA x0=[2 2]'; % tol=1e-6; miter=10000; % dxmin=1e-6; alpha=0.01; % gnorm=inf; x=x0; niter=1; ...
quasi 4 anni fa | 0
Domanda
value in each iteration
f=@(x) 0.5*(x(1)-1).^2+10*(x(2)+2).^2-2 miter=10000 and i have loop for i=1:miter then,who i can to calculate f(i)-f(i-1)...
quasi 4 anni fa | 1 risposta | 0
1
rispostaDomanda
function of two variables
i had a function with two variables f(x1,x2) in loop for k times how can i calculate the value of the function in each iterati...
quasi 4 anni fa | 1 risposta | 0
1
rispostaDomanda
stopping criterion in Gradient Descent Algorithm
For this unconstrainted objective function and, the stopping criterion is How can i implement it in Matlab code?? Than...
quasi 4 anni fa | 0 risposte | 0
0
risposteDomanda
how can i call and plot function of two variables ?
For this equation: i want to write it as a function and then call and plot it in another file
quasi 4 anni fa | 1 risposta | 0
1
rispostasolving problem for gradient descent
at the last of the code , why g = 4*(x(1).^2 + x(2)-x(3)).^2 +10; you didnt grad it?
quasi 4 anni fa | 1