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Hashem Burki


Attivo dal 2011

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Domanda


How to use your own code in simulink
i have a code and i want to add it to my simulink mode. How can i do it?

oltre 13 anni fa | 4 risposte | 0

4

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Risposto
processing on a live webcam streaming video???
what i ment was that i want to perform a skin segmentation code on an input webcam video, and want to preview it as an output vi...

oltre 13 anni fa | 0

Domanda


Image difference and magnitude.
I need to take the difference of two images. Such that image1 is a normal image and image2 is a somewhat skewed. I then want to ...

oltre 13 anni fa | 1 risposta | 0

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risposta

Domanda


How can i get a magnitue of an image?
I have got a grayscale image and i want to find its magnitude. As in that image should return a single scalar number.

oltre 13 anni fa | 1 risposta | 0

1

risposta

Domanda


processing on a live webcam streaming video???
I am using an image acquisition toolbox to obtain the live stream from my webcam. I have my own code for skin color segmentation...

oltre 13 anni fa | 3 risposte | 0

3

risposte

Domanda


detecting the x and y co-ordintes of a hand and finger from webcam
is it possible to detect the x and y co-ordintes of a hand and fingers from webcam?

oltre 13 anni fa | 3 risposte | 0

3

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Domanda


taking input from two cameras at a same time in Matlab
how can i use and take input from two cameras at the same time?

oltre 13 anni fa | 4 risposte | 2

4

risposte

Domanda


video segmentation code
Hi, I'm trying to build a touchscreen using cameras. I would like to know if there is a segmentation method in which i am able t...

oltre 13 anni fa | 0 risposte | 0

0

risposte

Domanda


Segmentation using homography?
Is it possible to achieve segmentation using two views through homography? e.g if i want to achieve segmentation of a hand by co...

oltre 13 anni fa | 0 risposte | 0

0

risposte

Domanda


How to read jpg images in a loop
Hi, I'm new in this. I have 4 images named: img1.jpg, img2.jpg, img3.jpg, and img4.jpg. All i have to do is read them one by one...

oltre 13 anni fa | 2 risposte | 0

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