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Liber-T


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MATLAB Answers

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Function to find the more recurrent number
Hye, I have a matrix 1 by (a big number, like 1000), and I would like to extract the element of the matrix that appears most of ...

oltre 14 anni fa | 4 risposte | 0

4

risposte

Domanda


Fsolve more effective.
Hye, I would like to make Fsolve more effective when it solves complex root of complex function, is their a way?

oltre 14 anni fa | 1 risposta | 0

1

risposta

Domanda


more than one input in sprintf
Hye, I would like to put two argument in sprintf. I tried: sprintf('mu=%s ,nu/omega=%s',mu1,q) but it doesn't work, on...

oltre 14 anni fa | 2 risposte | 0

2

risposte

Domanda


The title of a figure
Hye, How could I give a title to a figure that depend on the input of the function that create the figure.

oltre 14 anni fa | 2 risposte | 2

2

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Domanda


Function producing two figure
Hye, I made a function who gives 6 plot. I know how to post them all in one figure by using subplot. But I would like to post t...

oltre 14 anni fa | 1 risposta | 0

1

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Domanda


Matlab function
*I need to solve a problem, here are my need:* -To find the zeros of a function -The function is complex -The zeros are compl...

oltre 14 anni fa | 3 risposte | 0

3

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Domanda


Solve DET and ODE faster
[EDIT: 20110617 14:03 CDT - reformat - WDR] Hye I made a set of function, but it is too slow or innacurate. Here are the functi...

oltre 14 anni fa | 1 risposta | 0

1

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Domanda


fsolve
Is there a way to accelerate the fsolve function, with the least lost of precision possible. In: beta(n+1)=fsolve(F,beta(n))

oltre 14 anni fa | 2 risposte | 0

2

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Domanda


Faster than ODE45
I would like to go faster than ode45 and ode 23 is there a way to change the input in: [t,y]=ode23tb(@Gi,[0.000001;a],[1,0]);...

oltre 14 anni fa | 1 risposta | 0

1

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Domanda


Complex root of nonlinear complex equation containing besselh
I need to find the complex number which will make the real part of the function and the imaginary part, both equals 0. I have ...

oltre 14 anni fa | 0 risposte | 0

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