rjnt Kaur

Attivo dal 2013

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Domanda

How to write matlab code for modular multiplicative inverse in cryptography
Hello Professionals ... Can anyone help in how to write matlab code for following ... ...

oltre 12 anni fa | 3 risposte | 1

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where my code is wrong
i want to display a which has char value 97 but at output side it doesnot come 97

oltre 12 anni fa | 0

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where my code is wrong
l_mod is m file for module...for example i have to calculate c^e mod f then mod(c,e,m) is calculated using m file of mod

oltre 12 anni fa | 0

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where my code is wrong
l_mod is mfile for cryptography without this mod cannot be calculated ...because i am doing this for example c^e mod m

oltre 12 anni fa | 0

Domanda

where my code is wrong
hello professionals can you plz help me in this code i want to display a at decrypted part but there is no value .plz help in c...

oltre 12 anni fa | 4 risposte | 0

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Domanda

please help me how to write code for this for cryptography
NEED MATLAB CODE FOR CRYPTOGRAPHY FOR FOLLOWING EQUATION t=a^(b^c mod d)*r^m(mod m^2)

oltre 12 anni fa | 1 risposta | 0

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Domanda

what is the matlab code for follwing equation
t=s^e(mod n) u=m*m c=(g^t)*r^m mod u

oltre 12 anni fa | 1 risposta | 0

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Domanda

how to convert float value(0.68) to real one
need matlab code for converting float value to real value..or make the code to calculate only real value..please suggest regardi...

oltre 12 anni fa | 0 risposte | 0

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Domanda

hello professinals suggest me matlab code
help me how to write or send me matlab code for e*dp-kp1*kp2(p-1)=1....if this equation then display e and kp2 where dp,kp1 and ...

oltre 12 anni fa | 1 risposta | 0

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Domanda

hi professoinals.....how to run this code
%Calculate the value of e and kp2 p=3 kpi=4 dp = 5 kp2=rand(10); e=rand(10); for i=1:1 j=1:5 ...

oltre 12 anni fa | 3 risposte | 0

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Domanda

hello professionals can you please help me how to make matlab code for following equation
I want to satistisfy the equation e*dp-kp1*kp2*(p-1)=1.... the value of dp,kp1 and p are previously calculated my code...

oltre 12 anni fa | 1 risposta | 0

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hi professoinals.....how to run this code
Thanks Florian for your valueable time ...i want to satistisfy the equation e*dp-kp1*kp2*(p-1)=1....my code is not generating r...

oltre 12 anni fa | 0

Domanda

hello professionals ..i have aattached my code plz suggest me why it is not displaying value of kp2 and e
kp2=rand(10); e=rand(10); for i=1:length(50) r=e(i)*dp-kp1*kp2(i)*(p-1); if r==1 break; end end ...

oltre 12 anni fa | 1 risposta | 0

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Domanda

hello professionals ..i have attached my code plz suggest me why it is not displaying value of kp2 and e as it is not entering the loop
kp2=rand(10); e=rand(10); for i=1:length(50) r=e(i)*dp-kp1*kp2(i)*(p-1); if r==1 break; end...

oltre 12 anni fa | 0 risposte | 0

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Domanda

hello professionals plz help me why my code is not showing the value of kp2 and e
kp2=rand(10); e=rand(10); for i=1:length(50) r=e(i)*dp-kp1*kp2(i)*(p-1); if r==1 break; end end ...

oltre 12 anni fa | 1 risposta | 0

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Domanda

loop for equation a*b-c*d*(p-1)=1
I need matlab loop code for equation a*b-c*d*(p-1)=1 where a nad c are randomly selected and b,d and p are calculated previously...

oltre 12 anni fa | 1 risposta | 0

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Domanda

need help on calculating complexity ,speed and time needed by given code
Hello professionals...i need help on how to calculate the comlexity,speed and time spent on calculation of matlab code.can u plz...

oltre 12 anni fa | 1 risposta | 0

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i need help on making loop for given equation
Thanks alot for your suggested code..it works..but i forget to write one thing..the actual equation is a*b-c*d*(t-1)=1 where a a...

oltre 12 anni fa | 0

Domanda

need help on equation a*b-c*d(t-1)=1....
hello professionals....i need help on equation a*b-c*d(t-1)=1....where a and c are selected randomly and b , d and t are previ...

oltre 12 anni fa | 1 risposta | 0

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Domanda

i need help on making loop for given equation
hello professionals.. I have problem in making loop for given equation ab-cd=1..in this i have to choose...

oltre 12 anni fa | 2 risposte | 0

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