how to calculate the major and minor axis of an ellipse in contour plot

12 visualizzazioni (ultimi 30 giorni)
I have a contour plot which is more of a ellipse.I would like to know its major and minor axis...a and b respectively.How do i go about.I am naive user please guide me.

Risposta accettata

Image Analyst
Image Analyst il 14 Nov 2013
You need the Image Processing Toolbox. Type ver to see if you have it.
It looks like an indexed image with a jet colormap being applied. Get one "ring" by thresholding
binaryImage = grayImage == theValue; % Different rings will have different intensity values.
% Now get the ellipse parameters with regionprops.
measurements = regionprops(binaryImage, 'MajorAxisLength', 'MinorAxisLength', 'Orientation');
majorAxisLength = measurements.MajorAxisLength;
minorAxisLength = measurements.MinorAxisLength;
% Repeat for other rings.

Più risposte (2)

Mohammad Bhat
Mohammad Bhat il 11 Feb 2018
How can I pass ellipse as an object to regionprops
  3 Commenti
Rahul  Verma
Rahul Verma il 6 Gen 2020
I am having a similar contour image which I converted to grayscale as attached...
a=imread('test1.png');
grayImage = rgb2gray(a);
grayscale.pngbinaryImage = grayImage == 0.40;
measurements = regionprops(binaryImage, 'MajorAxisLength', 'MinorAxisLength', 'Orientation');
However, on calling regionprops, I get an empty matrix
0×1 empty struct array with fields:
MajorAxisLength
MinorAxisLength
Orientation
As a result, I cannot get the major and minor axis lengths...
Any suggestions :)test1.png
Image Analyst
Image Analyst il 6 Gen 2020
You probably don't have anything that is EXACTLY 0.4. Try
binaryImage = grayImage >= 0.40;
Do it again for a different value and AND the images if you just want the ring.
binaryImage = grayImage >= 0.40 & grayImage <= someOtherValue;

Accedi per commentare.


Bhavesh Garg
Bhavesh Garg il 12 Gen 2021
VHVHV

Categorie

Scopri di più su Image Processing Toolbox in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by