Matlab approximation of 0 for small numbers

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Mark
Mark il 27 Nov 2013
Commentato: Mark il 15 Gen 2014
Hi,
I'm attempting to check for error convergence, but I'm entering an infinite loop, and I believe the culprit is Matlab approximating a small number as 0. These numbers are used in the calculation of my error,
xx = 1 - ((ff*ddff)/(2*dff*dff))
bb = ((ff*ddff)/(2*dff*dff)) % for display and debugging purposes only
But for some early iterations I get stuck in an infite loop and the outputs are
xx =
1
bb =
-1.2633e-08
This in turn affects the error calculation (decreasing the tolerance of my error fixes the situation but this is not desireable). Clearly the theoretical answer of xx is not exactly 1 (as the output format suggests, shouldn't it display 1.000?). Would matlab be approximating bb = 0 in this case? Any way to change the approximation tolerance? Any help is appreciated.
Mark

Risposta accettata

Mark
Mark il 10 Gen 2014
I had read data in as %f32 instead of %f64 thus not recognizing that small of a number
  2 Commenti
Marc
Marc il 10 Gen 2014
How is that an "accepted" answer? You did not ask us how to read in data.
Mark
Mark il 15 Gen 2014
I asked why matlab was approximating numbers as zero when it should have been keeping its finite value. The format of the data was important because when calculations gave such small enough answers it would register as 0. I know how to read in data, my question was how matlab handles it. See floating point double vs. floating point single.

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Più risposte (1)

Sean de Wolski
Sean de Wolski il 27 Nov 2013
while abs(bb)<10^-7
etc.
end
?
  2 Commenti
Mark
Mark il 27 Nov 2013
the xx value is used in a different calculation where small changes in xx would have a larger change in the resulting calculation. It is the difference between these 2 iterations/calculations that I'm trying to get to converge (i.e. <1e-6)
Sean de Wolski
Sean de Wolski il 27 Nov 2013
Then include that expression inside of the abs()

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