Azzera filtri
Azzera filtri

fprintf error:function not defined for struct inputs

2 visualizzazioni (ultimi 30 giorni)
Tomas
Tomas il 5 Dic 2013
Commentato: Tomas il 5 Dic 2013
I have an input argument that is a 1x1 struct
this is my code
function escrevecircuitos(circuito, fid)
if fid == 1 fprintf(fid,'%8s %13s %2s %2s %9s %7s\r\n', 'circuito', 'nome_ficheiro', 'SE', 'ID', 'Perimetro', 'Recorde'); for i = 1:length(circuito) fprintf('%20s %14.1s %2.6f %1.6f %2.6f %1.6f %4d %1:2:3f\r\n',circuito(i).circuito,circuito(i).nome_ficheiro,circuito(i).SE(1),circuito(i).ID,circuito(i).Perimetro,circuito(i).Recorde); end end
How can i solve the problem,the error is
Error using fprintf Function is not defined for 'struct' inputs.
Error in escrevecircuitos (line 7) fprintf('%20s %14.1s %2.6f %1.6f %2.6f %1.6f %4d %1:2:3f\r\n',circuito(i).circuito,circuito(i).nome_ficheiro,circuito(i).SE(1),circuito(i).ID,circuito(i).Perimetro,circuito(i).Recorde)
Thank you for the help

Risposte (1)

Walter Roberson
Walter Roberson il 5 Dic 2013
That looks okay at the moment, unless one of the fields inside circuito is itself a structure. Perhaps circuito(i).circuito or circuito(i).Perimetro
Try this to help debug
fn = fieldnames(circuito);
for K = 1 : length(circuito)
for f = 1 : length(fn)
if isstruct( circuito(K).(fn{f}) )
fprintf('Index %d field %s is structure\n', K, fn{f} );
end
end
end
  1 Commento
Tomas
Tomas il 5 Dic 2013
both circuito(1).SE and circuito(i).ID are 1x1 structures,
how can solve this?i need the fprintf to give me the two values inside SE and ID

Accedi per commentare.

Categorie

Scopri di più su Data Type Conversion in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by