# Problem using ezplot function

6 views (last 30 days)
Sudipta Basu on 11 Dec 2013
Commented: sixwwwwww on 11 Dec 2013
I am having a for loop. I want to draw a graph using ezplot for a function like this: f(x) = sin(x) (0<x<pi/4) f(x) = cos(x) (pi/4<x<pi/2) that is the function is having different definition at different intervals. But, I am getting the graph in two separate figures instead of one figure. Please help.
A part of the code is provided below: syms x t1 = 0; for i = 1:n t2 = t1+L(i); if option(i)==1 R(i)=(-(M(i,1)+M(i,2))+q(i)*L(i)^2/2)/L(i); Vx = R(i)-q(i)*x; else R(i)=(-(M(i,1)+M(i,2))+q(i)*L(i)^2/3)/L(i); qx = (1-x/L(i))*q(i); Vx = R(i) - 0.5*(qx+q(i))*x; end figure; hold on; ezplot(Vx,[t1 t2]); t1 = t1+L(i); end
sixwwwwww on 11 Dec 2013
values of n, L, option etc. are missing. Please include these values so that your code can run properly

sixwwwwww on 11 Dec 2013
replace this:
figure; hold on;
ezplot(Vx,[t1 t2]);
with
ezplot(Vx,[t1 t2]), hold on
It will keep the old plot as it is and will add new plot to the same figure