Generating integer random numbers from power-law distribution

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Is there a code to generate integer random numbers through power-law distribution of the form p(x)=x^-(alpha+1)?
thanks in advance

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Image Analyst
Image Analyst il 13 Dic 2013
Try this: RANDRAW

Più risposte (3)

Miguel Ángel
Miguel Ángel il 13 Dic 2013
Modificato: Miguel Ángel il 13 Dic 2013
I don't know if round,ceil or floor is correct, but in case this may be a way
n=1000;
p=rand(1,n);
alpha=0.1;
%inverse of distribution
%properties of logs %LOGa(n) = LOGb(N) / LOGb(a)
%~round/ceil/floor
x=round(log(p)/log(alpha+1));
  1 Commento
Sunstar
Sunstar il 13 Dic 2013
Thank you for your reply. Unfortunately, I cannot simply round or floor or ceil. I need to generate real integers.

Accedi per commentare.


Roger Stafford
Roger Stafford il 13 Dic 2013
The distribution you mention is equivalent to the zeta distribution with alpha+1 replaced by s. See the website
http://en.wikipedia.org/wiki/Zeta_distribution
As Image Analyst has mentioned, there is a File Exchange contribution called 'randraw' which is located at:
http://www.mathworks.com/matlabcentral/fileexchange/7309-randraw
which claims to generate random numbers in accordance with fifty various distributions including the zeta distribution. It might be what you need.

Weijia Chen
Weijia Chen il 18 Set 2019
I also meet the same problem. The minimum integer that zeta distribution can generate seems to be 1, but I hope 0 can be generated. Is there any other distributin can do this? Thank you

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