- polygons (everything is a polygon)
- quadrilaterals, polygons, and ellipsoids
- quadrilaterals, rectangles, polygons, and ellipsoids
- quadrilaterals, rectangles, polygons, circles, and ellipsoids
- quadrilaterals, rectangles, squares, polygons, circles, and ellipsoids
How to detect the shape in matlab?
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saravanakumar D
il 27 Dic 2013
Modificato: DGM
il 13 Feb 2023
I can't understand the technique how to analyse the shape. So any please help me to understand this concept.
Code is below
function W = Classify(ImageRead)
RGB = imread('test.bmp');
figure,
imshow(RGB),
title('Original Image');
GRAY = rgb2gray(RGB);
figure,
imshow(GRAY),
title('Gray Image');
threshold = graythresh(GRAY);
BW = im2bw(GRAY, threshold);
figure,
imshow(BW),
title('Binary Image');
BW = ~ BW;
figure,
imshow(BW),
title('Inverted Binary Image');
[B,L] = bwboundaries(BW, 'noholes');
STATS = regionprops(L, 'all'); % we need 'BoundingBox' and 'Extent'
% Step 7: Classify Shapes according to properties
% Square = 3 = (1 + 2) = (X=Y + Extent = 1)
% Rectangular = 2 = (0 + 2) = (only Extent = 1)
% Circle = 1 = (1 + 0) = (X=Y , Extent < 1)
% UNKNOWN = 0
figure,
imshow(RGB),
title('Results');
hold on
for i = 1 : length(STATS)
W(i) = uint8(abs(STATS(i).BoundingBox(3)-STATS(i).BoundingBox(4)) < 0.1);
W(i) = W(i) + 2 * uint8((STATS(i).Extent - 1) == 0 );
centroid = STATS(i).Centroid;
switch W(i)
case 1
plot(centroid(1),centroid(2),'wO');
case 2
plot(centroid(1),centroid(2),'wX');
case 3
plot(centroid(1),centroid(2),'wS');
end
end
return
0 Commenti
Risposta accettata
Image Analyst
il 27 Dic 2013
What are the kinds of shapes you have there?
You might look at the solidity, area, and perimeter. And the circularity = perimeter.^2 ./ (4*pi*area).
You may also find this useful to determine how many sides a polygon has: http://matlab.wikia.com/wiki/FAQ#How_do_I_find_.22kinks.22_in_a_curve.3F
7 Commenti
José Hugo Soares de Jesus
il 12 Mag 2022
Good Afternoon, I want to to do the code by myself, I want just to know what´s the range of circularity of a triangle, pentagon and hexagon?
Image Analyst
il 12 Mag 2022
Then run the demo I attached. It shows you the circularity of a variety of shapes and sizes. Because you're asking I assume you didn't run it or else you'd know the answer.
Più risposte (4)
Shawn Fernandes
il 21 Mar 2018
Modificato: DGM
il 13 Feb 2023
Hi All,
Bounding box gives the smallest possible rectangle / cuboid that fits the given shape, and would support n dimensions. [x_cordinate,y_cordinate,z_cordinate,....nth_cordinate,x_width,y_width,z_width.....nth_width] in this 2 D image, we have bounding box defined for each shapes as [x_cordinate,y_cordinate,x_width,y_width]
Extent gives the ratio of area of the bounding box to area of the region. For squares and rectangles, as the bounding box matches the shape, extent = 1. For circles and ellipses, the ratio of area of region to bounding box is always a constant = pi/4, [ (pi * a * b) / (2*x * 2 * y) is extent of circular region, for circle, a = b = x =y, for ellipse, a=x and b =y ]
So
(1)for Circles, we have x_width = y_width,extent = pi/4
(2)for squares, we have x_width = y_width,extent =1,
(3)for rectangles, we have x_width != y_width,extent =1
(4)For ellipse, we have we have x_width != y_width,extent = pi/4
Reference:-
the below code has been tested and it works
for i = 1 : length(STATS)
centroid = STATS(i).Centroid;
if((STATS(i).BoundingBox(3)~=STATS(i).BoundingBox(4)) && (STATS(i).Extent<1))
plot(centroid(1),centroid(2),'w+');
text(centroid(1),centroid(2),num2str(i),'Color','y');
end
if((STATS(i).BoundingBox(3)==STATS(i).BoundingBox(4)) && (STATS(i).Extent==1))
plot(centroid(1),centroid(2),'wS');
text(centroid(1),centroid(2),num2str(i),'Color','y');
end
if((STATS(i).BoundingBox(3)==STATS(i).BoundingBox(4)) && (STATS(i).Extent > 0.76 && STATS(i).Extent < .795))
plot(centroid(1),centroid(2),'wO');
text(centroid(1),centroid(2),num2str(i),'Color','y');
end
if((STATS(i).BoundingBox(3)~=STATS(i).BoundingBox(4)) && (STATS(i).Extent==1))
plot(centroid(1),centroid(2),'wX');
text(centroid(1),centroid(2),num2str(i),'Color','y');
end
if((STATS(i).BoundingBox(3)~=STATS(i).BoundingBox(4)) && (STATS(i).Extent > 0.76 && STATS(i).Extent < .795))
plot(centroid(1),centroid(2),'w*');
text(centroid(1),centroid(2),num2str(i),'Color','y');
end
end
Hope this helps..
9 Commenti
Image Analyst
il 30 Dic 2022
@Joman depends on what you want the result to show. You could use a marker symbol and plot to put a marker at the centroid of the shape. Or you could use text to put the word for the shape at the centroid. Or you could extract each type of shape (by color or number of vertices) to its own separate image.
sss
il 26 Dic 2016
Modificato: Image Analyst
il 26 Dic 2016
what is the meaning of this for loop? -----
for i = 1 : length(STATS)
W(i) = uint8(abs(STATS(i).BoundingBox(3)-STATS(i).BoundingBox(4)) < 0.1);
W(i) = W(i) + 2 * uint8((STATS(i).Extent - 1) == 0 );
centroid = STATS(i).Centroid;
switch W(i)
case 1
plot(centroid(1),centroid(2),'wO');
case 2
plot(centroid(1),centroid(2),'wX');
case 3
plot(centroid(1),centroid(2),'wS');
end
1 Commento
Image Analyst
il 26 Dic 2016
It plots w0, wx, or xS at the centroid of blobs in a binary image. If the blob is roughly square it puts a wS at the centroid. If it's a rectangle it will put up wX. Otherwise it will put up w0 for arbitrarily-shaped blobs that fit in a bounding box that is roughly square. I don't see anything being put up for arbitrarily-shaped blobs that have a rectangular bounding box.
Syukri Yazed
il 17 Mag 2021
Spostato: Image Analyst
il 30 Dic 2022
Hi,
I've tested your code and improved it with the code that have been answered previously..
%https://ch.mathworks.com/matlabcentral/answers/110855-how-to-detect-the-shape-in-matlab
%https://ch.mathworks.com/matlabcentral/answers/245026-shape-detection-in-image
clc
%clear all
close all
%function W = Classify(ImageRead)
baseFileName = 'F:\PhD\MATLAB CODING\BlobsDemo\shape.png';
RGB = imread(baseFileName);
subplot(3, 3, 1);
imshow(RGB),
title('Original Image');
GRAY = rgb2gray(RGB);
subplot(3, 3, 2);
imshow(GRAY),
title('Gray Image');
threshold = graythresh(GRAY);
BW = imbinarize(GRAY, threshold);
subplot(3, 3, 3);
imshow(BW),
title('Binary Image');
BW = ~ BW;
subplot(3, 3, 4);
imshow(BW),
title('Inverted Binary Image');
[B,L] = bwboundaries(BW, 'noholes');
STATS = regionprops(L, 'all'); % we need 'BoundingBox' and 'Extent'
% Step 7: Classify Shapes according to properties
% Square = 3 = (1 + 2) = (X=Y + Extent = 1)
% Rectangular = 2 = (0 + 2) = (only Extent = 1)
% Circle = 1 = (1 + 0) = (X=Y , Extent < 1)
% UNKNOWN = 0
subplot(3, 3, 5);
imshow(RGB),
title('Results');
hold on
for i = 1 : length(STATS)
centroid = STATS(i).Centroid;
if((STATS(i).BoundingBox(3)~=STATS(i).BoundingBox(4)) && (STATS(i).Extent<1))
plot(centroid(1),centroid(2),'w+');
text(centroid(1),centroid(2),num2str(i),'Color','y');
end
if((STATS(i).BoundingBox(3)==STATS(i).BoundingBox(4)) && (STATS(i).Extent==1))
plot(centroid(1),centroid(2),'wS');
text(centroid(1),centroid(2),num2str(i),'Color','y');
end
if((STATS(i).BoundingBox(3)==STATS(i).BoundingBox(4)) && (STATS(i).Extent > 0.76 && STATS(i).Extent < .795))
plot(centroid(1),centroid(2),'wO');
text(centroid(1),centroid(2),num2str(i),'Color','y');
end
if((STATS(i).BoundingBox(3)~=STATS(i).BoundingBox(4)) && (STATS(i).Extent==1))
plot(centroid(1),centroid(2),'wX');
text(centroid(1),centroid(2),num2str(i),'Color','y');
end
if((STATS(i).BoundingBox(3)~=STATS(i).BoundingBox(4)) && (STATS(i).Extent > 0.76 && STATS(i).Extent < .795))
plot(centroid(1),centroid(2),'w*');
text(centroid(1),centroid(2),num2str(i),'Color','y');
end
end
%return
Could you please share with us your succesful code in detecting the shapes? Because I don't know the result numbering for.. what is wO, wX, w*, wS, w+?
or maybe Shawn Fernandes and ImageAnalyst can comment something regarding this matter.
1 Commento
Image Analyst
il 18 Mag 2021
Spostato: Image Analyst
il 30 Dic 2022
what is wO, wX, w*, wS, w+?
Those are plot colors and marker shapes. See the plot() function documentation.
- wo = white circles
- wx = white x's
- w* = white stars
- ws = white squares
- w+ = white plus signs.
Beenish Ishtiaq
il 3 Ago 2021
How to detect the shape using GUI
1 Commento
Image Analyst
il 3 Ago 2021
I'm attaching my shape recognition demos. Adapt as needed.
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