How to create user defined function in matlab?
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saravanakumar D
il 22 Gen 2014
Commentato: Image Analyst
il 23 Gen 2014
I have use below set of code frequently. So i have to make user defined function
below is my frequently used code:-
x=xvalue;
y=yvalue;
for j=1:3;
red(j)=RGB(y,x,j);
end
shape.color=red;
2 Commenti
Azzi Abdelmalek
il 22 Gen 2014
Can you explain what are the argument (inputs and outputs) of your function?
Risposta accettata
Image Analyst
il 22 Gen 2014
Modificato: Image Analyst
il 22 Gen 2014
I think this is the minimum necessary:
function shape = myFunction(RGB, xvalue, yvalue, i)
x=xvalue;
y=yvalue;
for j=1:3;
red(j)=RGB(y,x,j);
end
shape(i).color=red;
Optionally, x, y, and red could also be outputs, and shape could also be an input. Be aware that the "red" variable actually contains the red, green, and blue values from the pixel at (y, x).
6 Commenti
Walter Roberson
il 23 Gen 2014
shape.color=red;
creates "shape" as a structure with a field "color" that it sets to the content of "red". Then your statement
shape=shape.color
overwrites "shape" with the contents of the field "color", into which you had written the content of "red". The net effect of your code is as the same as if you had changed those last two lines to
shape = red;
Image Analyst
il 23 Gen 2014
Do you want a structure or not? If there is only one field, then I see no reason at all to use a structure. Just use a simple variable.
Più risposte (1)
Walter Roberson
il 22 Gen 2014
function shape = myFunction(RGB, xvalue, yvalue, i)
shape(i).color = squeeze(RGB(xvalue, yvalue, :));
2 Commenti
Walter Roberson
il 22 Gen 2014
The output variable is "shape", as listed in the function header. The "shape" that is output will be a structure array with a single field "color", with the "i"th element of the structure array populated with meaningful data and the rest of the shape(K).color will be the empty array []
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