METHOD FOR PREDICTION DATA

HELLO I need help please ihave Data of Gps position and iwant to use predictor to the GPS which method ican use and what is the algorithm of the method.
[EDIT]
at first i have program but something wrong in this program please help me to repair it to compute position ( x,y,z) i know ph, xsv.ysv.zsv and i want to compute x.y,z
for i = 1: 19
ph(i) = sqrt((xSV(i) - x)^2 + (ySV(i) - y)^2 + (zSV(i) - z)^2)
end
% Compute the H matrix % for i = 1: 19 % % dph_x denote dph(i)/dx % dph_x = -(xSV(i) - x) / ((xSV(i) - x)^2 + (ySV(i) - y)^2 + (zSV(i) - z)^2)^(0.5); % dph_y = -(ySV(i) - y) / ((xSV(i) - x)^2 + (ySV(i) - y)^2 + (zSV(i) - z)^2)^(0.5); % dph_z = -(zSV(i) - z) / ((xSV(i) - x)^2 + (ySV(i) - y)^2 + (zSV(i) - z)^2)^(0.5); % % H(i,:)=[dph_x dph_y dph_z 1]; %end % i % DeltaX = (H') * (ph - ph1)'; % x = DeltaX(1) + x; % y = DeltaX(2) + y; % z = DeltaX(3) + z; % cdtr = DeltaX(4) ;
%end %k
r = [x y z]'; %location = ecef2lla2(r); location = r;

2 Commenti

omar
omar il 24 Gen 2014
here is the program that ineed to help me to correct it for i = 1: 19 ph(i) = sqrt((xSV(i) - x)^2 + (ySV(i) - y)^2 + (zSV(i) - z)^2) end % Compute the H matrix for i = 1: 19 % % dph_x denote dph(i)/dx % dph_x = -(xSV(i) - x) / ((xSV(i) - x)^2 + (ySV(i) - y)^2 + (zSV(i) - z)^2)^(0.5); % dph_y = -(ySV(i) - y) / ((xSV(i) - x)^2 + (ySV(i) - y)^2 + (zSV(i-z)^2)^(0.5); dph_z = -(zSV(i) - z) / ((xSV(i) - x)^2 + (ySV(i) - y)^2 + (zSV(i) - z)^2)^(0.5); % % H(i,:)=[dph_x dph_y dph_z 1]; %end % i % DeltaX = (H') * (ph - ph1)'; % x = DeltaX(1) + x; % y = DeltaX(2) + y; % z = DeltaX(3) + z; % cdtr = DeltaX(4) ;
r = [x y z]'; %location = ecef2lla2(r); location = r;
Image Analyst
Image Analyst il 24 Gen 2014
Looks like a mess. Just attach with the paperclip icon.

Accedi per commentare.

Risposte (2)

Walter Roberson
Walter Roberson il 23 Gen 2014

0 voti

Find the mean latitude and standard deviation in latitude, and likewise for longitude. Use the mean position as a base position, randonly generate a normally distributed latitude based on the standard deviation in latitude, and randomly generate a normally distributed longitude based on the standard deviation in longitude. You have now made a prediction.

1 Commento

Image Analyst
Image Analyst il 24 Gen 2014
omar's "Answer" moved here:
hello thanks for your answer please ineed example about your answer and the program used matlab about prediction which algorithm ican use please

Accedi per commentare.

Image Analyst
Image Analyst il 24 Gen 2014

0 voti

Are you trying to interpolate data, or extrapolate data? Are you trying to track some object/vehicle? You seem rather tight lipped about your project - if you can supply more info that would help us help you. Don't make it hard for us.

Richiesto:

il 23 Gen 2014

Commentato:

il 24 Gen 2014

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