Finding values in an Array

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Aldo Amaya
Aldo Amaya il 30 Gen 2014
Commentato: Aldo Amaya il 30 Gen 2014
If I have an array such as
Subject= [126;156;1992, 203, 186] % First two digits determine group, additional numbers are specific subject within that group.
Is there a method to only read the first two values of each row in order to determine what group the subject is?
Group= [12;15;19;20;18] %%%This is what I would like the result to be.

Risposta accettata

Jos (10584)
Jos (10584) il 30 Gen 2014
Apply some arithmetic:
Subject = [126 156 1992 203 186 10 100 100000]
Group = fix(Subject ./ (10.^floor(log10(Subject)-1)))

Più risposte (2)

Walter Roberson
Walter Roberson il 30 Gen 2014
Group = floor(Subject ./ 10);
  1 Commento
Aldo Amaya
Aldo Amaya il 30 Gen 2014
Thanks for the reply, the only issue is that they are not all the same number of elements. Subjects elements range from 3-5 currently.

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Aldo Amaya
Aldo Amaya il 30 Gen 2014
Modificato: Aldo Amaya il 30 Gen 2014
This was my solution but I wish there was a cleaner way to do it
Group = floor(Namex2 ./ 10);
i=1;
while i<=length(Group)
if Group(i)>=100
Group(i)=floor(Group(i)./ 10);
else
end
i=i+1;
end

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