having trouble with for loops

 Risposta accettata

out = 1;
for ii = 2:1000
out = out + ii^2;
end

3 Commenti

SumN=0; % initializes N^2
for N=1:1000
SumN = SumN + N^2;
end
Still not giving me correct answer...Don't know what I'm doing wrong
Thomas
Thomas il 13 Feb 2014
what answer do u expect?
Joseph
Joseph il 13 Feb 2014
i got it thanks

Accedi per commentare.

Più risposte (2)

Here's a way to check your answer:
n = 1000;
s = n*(n+1)*(2*n+1)/6;
This gives you the same value as
s = sum((1:n).^2);
Alonso Mukendi Kalonji
Alonso Mukendi Kalonji il 29 Ott 2022

0 voti

a = 1;
n= 1000;
for i = 1: n
a = a+i^2
end
disp(a)

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