Having problems with lsqnonlin function

Hello guys, I have an equation I am trying to fit to voltage and current. The problem that I have is that the equation has the current (Jcal) in both sides of the equation and I can't simplify the equation. Is there a way to bypass this problem and have MatLab fit the equation to data? I have four unknowns and here is what the program looks like.
J=current(1,:);
V=voltage(1,:);
q=1.60e-19; % C
k=1.38e-23; % m2 Kg s-2 K-1
T=298; % Kelvin
L0=[2 0.1 0.1 0.1];
L=lsqnonlin('recfun',L0);
Jcal=L(4)/(L(4)+L(3))*(L(2)*(exp(q*(V-Jcal*L(3))/L(1)*k*T)-1)+V/L(4));
Thanks,
Francisco

2 Commenti

To fit an equation to data, you need to have some parameters that you can vary. But as far as I can tell from the above code, all the parameters are fixed - unless there is something I need to know about "recfun".
Hey Andrew,
I am varying several parameters, actually four! :) Which may too many for one single equation, but I guess it's worth trying!! ;) I am fitting the values of J and V to the equation by varying the values of L.
Francisco

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 Risposta accettata

For whatever it is worth,
Jcal = (L(1)*(L(4)+L(3))*LambertW(q*k*T*L(3)*L(2)*L(4)*exp(T*(L(2)*L(4)*L(3)+V*L(4))*q*k/L(1)/(L(4)+L(3)))/L(1)/(L(4)+L(3))) - q*k*T*L(3)*(-V+L(2)*L(4)))/q/k/T/L(3)/(L(4)+L(3))

4 Commenti

Hey Walter,
I am not sure how you were able to simplify Jcal, but I will definitely look into this equation!! Maybe my math is too rusty and I forgot algebra!! :D Thanks for taking the time to write the equation in terms of Jcal only, can you illuminate me and tell me how you were able to extract Jcal from an exponent?
Francisco
Francisco
use Symbolic Toolbox (MuPAD)
>> solve('Jcal=L(4)/(L(4)+L(3))*(L(2)*(exp(q*(V-Jcal*L(3))/L(1)*k*T)-(1))+V/L(4))','Jcal')
ans =
(V - L(2)*L(4))/(L(3) + L(4)) + (L(1)*lambertw(0, (T*k*q*L(2)*L(3)*L(4)*exp((T*V*k*q)/L(1)))/(L(1)*exp((T*k*q*L(3)*(V - L(2)*L(4)))/(L(1)*(L(3) + L(4))))*(L(3) + L(4)))))/(T*k*q*L(3))
Yes, solved in the way Andrei indicates.
LembertW is a non-algebraic function suitable for solving y*exp(y)=x. It works well over a limited class of equations, but it doesn't take much of a tweak of the equation before it is unsuitable.
Awesome guys, I love MatLab now even more!! :)

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