Azzera filtri
Azzera filtri

Converting symbolic expression into double.

8 visualizzazioni (ultimi 30 giorni)
When I perform a series of functions, the result is:
1.009168*rS + 0.25*rS*dcellCurrent(1) + 0.157*rS*dcellCurrent(2) + 0.057*rS*dcellCurrent(3) - 0.002*rS*dcellCurrent(4) - 0.093*rS*dcellCurrent(5) - 0.145*rS*dcellCurrent(6) - 0.197*rS*dcellCurrent(7) - 0.232*rS*dcellCurrent(8) - 0.313*rS*dcellCurrent(9) ... *exp((120843*iSat*rSh)/(3125*n)))/(3125*n*exp((120843*rSh*dcellCurrent(13))/(3125*n))))
The expression is extremely long, I cut out a good bit of its innards so it would be viewable here. When I copy and paste the expression that it shows into the command window, the result is this number: 13.076812258420913
I know that I can just copy and paste it, but I would like to use logical expressions in an if statement, and I need to convert the expression in code because I would not like to do it by hand. How should I go about converting?

Risposta accettata

Sean de Wolski
Sean de Wolski il 19 Lug 2011
doc double
double(sym_expr)
and
doc subs

Più risposte (1)

Walter Roberson
Walter Roberson il 19 Lug 2011
You should use subs() to substitute the current values of the variables in to the expression, and you should use double() on the result to convert it from a symbolic number to a double precision value.
  6 Commenti
mkeehan
mkeehan il 19 Lug 2011
While the pain part of your answer makes me a bit nervous, it does work! Thank you both of you! How do I go about giving reputation?
Walter Roberson
Walter Roberson il 19 Lug 2011
You do not appear to have defined dcellCurrent.
Anyhow:
syms x dcC
S = simplify(solve(iP - iSat * (exp(38.66976*(x+dcC*rS)/n)-1) -(dcC*rS + x)/rSh - dcC));
subtotal = 0;
for K = 1:length(dcC)
subtotal = subtotal + (double(subs(S,dcC,dcellCurrent(K))-dcellVoltage(K)).^2;
end

Accedi per commentare.

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by