UDP Streaming Post Processing

Hi I have been following this tutorial and I wonder if anyone could explain the theory around the post processing as I don't seem to be able to process my data properly

http://www.mathworks.co.uk/help/xpc/examples/udp-data-streaming.html

I am streaming 1 double (digital clock) and 35 'single' signals through from my target machine into the PACK_DATA block

So I have set my data size to 148 and my packet size is 10

Thanks

Answer 1

[Suneesh]

Not quite sure what you mean by packet size = 10. DOUBLE are 64 bit. SINGLE are 32 bit. The data in UDP is represented as UNIT8. So you get a UINT8 packed size of 148.

148 * 8 = (64 * 1) + (32 * 35)

I am assuming you set up 'Input port data types' as {'double', 'single'}

If you send these out as UDP packets and then look at the packets using Wireshark you will see that each UDP packet has a data size of 148.

On the receive side its just the opposite of what was done for send. You set 'Output port dimensions' as {[1], [35]} and 'Output port data types' as {'double', 'single'}