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Bruno
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Problem with movavg "Not enough input arguments."

Asked by Bruno
on 28 Feb 2014
Latest activity Answered by Bruno
on 28 Feb 2014
Hello I am trying to calculate movavg as:
[lead,lag]=movavg(close,5,30);
I have the following:
Error using movavg (line 7) Not enough input arguments.
So if I try:
[lead,lag]=movavg(close,5,30,0);
I have:
Error using movavg (line 8) This function only supports exponential moving averages
So it only works if I use the following:
[lead,lag]=movavg(close,5,30,'e');
...BUT I want simple moving averages not exponential!!
This is strange since the syntax of the function is the following:
movavg(Asset, Lead, Lag, Alpha) [Short, Long] = movavg(Asset, Lead, Lag, Alpha)
Anybody can help me?

  1 Comment

I am wondering if I changed the original function using the files prepared by Stuart Kazola http://www.mathworks.com/matlabcentral/fileexchange/37932-automated-trading-with-matlab-2012
This is the code I have in movavg
function [lead,lag] = movavg(P,M,N,type) %#codegen % moving average, exponentially weighted.
%% % Copyright 2010, The MathWorks, Inc. % All rights reserved. if type ~= 'e' error('MOVAVG:TYPE','This function only supports exponential moving averages') end
L = length(P);
lead = zeros(size(P)); lag = lead;
ws = 2/(M+1); wl = 2/(N+1);
lead(1) = P(1); lag(1) = P(1);
% The for loop approach (slow for small-medium sized data series) for i = 2:L lead(i) = lead(i-1) + ws*(P(i) - lead(i-1)); lag(i) = lag(i-1) + wl*(P(i) - lag(i-1)); end

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1 Answer

Answer by Bruno
on 28 Feb 2014
 Accepted Answer

RESOLVED... the movavg.m prepared by Stuart Kazola conflicts with movavg.m Financial Toolbox R2013b

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