- The exact value 200 fits in two cases, amount5 and amount6
- add else to pick up mistakes
For loop to count matrix elements
2 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Hi all i'm trying to use a for loop ( for an assingmnet) to run through a 5000 element matrix ( which I've downloaded manually) and determine which variables fall under certain conditions ( hopefully they're apparent in the code). i think i've set everything up right but I'm getting output for only about 3700 numbers. also, i noticed i'm not getting any output for "f"... if x(n) > 200... even though i have several values that fall under this category in my matrix. any idea why this isn't working? i feel like it should be.
amount=0;
amount1=0;
amount2=0;
amount3=0;
amount4=0;
amount5=0;
amount6=0;
for n=1:length(x)
if x(n)>=0 && x(n)<= 30
amount=amount+1 ;
elseif x(n) >=30 && x(n)<=80
amount1=amount1+1 ;
elseif x(n) >= 80 && x(n)<=130
amount2=amount2+1 ;
elseif x(n) >= 130 && x(n) <= 150
amount3=amount3+1;
elseif x(n) >=150 && x(n)<=180
amount4=amount4+1 ;
elseif x(n) >= 180 && x(n) x<=200
amount5=amount5+1 ;
elseif x(n) >= 200
amount6=amount6+1 ;
end
end
% a,b,c,d,e,f are used to display final count values
a=amount
b=amount2
c=amount3
d=amount4
e=amount5
f=amount6
1 Commento
per isakson
il 14 Mar 2014
Modificato: per isakson
il 14 Mar 2014
Risposte (1)
Jos (10584)
il 14 Mar 2014
Why not use HISTC to count elements falling in a specific range?
amount = histc(x,[0 30 80 130 150 200 Inf])
0 Commenti
Vedere anche
Categorie
Scopri di più su Loops and Conditional Statements in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!