IF cell of a dataset equal to text

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Matthew
Matthew il 15 Apr 2014
Commentato: Matthew il 17 Apr 2014
Hi again.
I have a dataset with 100 rows of data with 4 columns.
I am trying to code the following and would like some help please:
For each row
If Table1.column1 = 'FOREX' (which is a string) and Table1.column4 < 0
then return Table1.column3 in Table1.column2
otherwise
If Table1.column1 = 'FOREX' (which is a string) and Table1.column4 >=0
then return Table1.column2 = (1% of Table1.column3) + Table1.column4
End

Risposta accettata

dpb
dpb il 15 Apr 2014
One (of many) way(s) to write it...
ix=strcmp(T.c1,'FOREX') & T.c4<0;
T(ix).c2=T(ix).c3;
ix=strcmp(T.c1,'FOREX') & T.c4>=0;
T.c2(ix)=0.01*T(ix).c3+T1(ix).c4;
Names abbreviated to protect...

Più risposte (1)

Matthew
Matthew il 16 Apr 2014
The above worked fine for numeric but I'm having a similar problem when I am wanting replace a field with text in the dataset. Can you help please?
iy=or(strcmp(CtpyList.deal_type,'120'), strcmp(CtpyList.deal_type,'123'));
This works fine and creates the table iy which details 0s or 1s when it meets the above condition.
CtpyList.customer_nr(iy) = CtpyList.Customer_nr_Sec(iy);
This works but it concatenates the cell i.e. customer_nr(iy) now reads: 1 NaN
Note that NaN has been converted to string.
Any ideas on how to totally replace this string NaN with the field in the corresponding row for Customer_nr_Sec??
  6 Commenti
dpb
dpb il 16 Apr 2014
Good; thought it might.
You do understand why, then???

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