Finding signal to noise ratio

I have a signal x=[34;56;12;87;35]

I have added some noise with the signal x. After denoising i have got the output

x0=[ 33.88;55;11.11;86.77;34.99]

Now how can i find out SNR? please help....

Answer 1

[Sven]

Hi Tinkul, does this help you out? I assume that the values you gave are already in your desired units (although true SNR is based on power of signals, not necessarily the signals themselves)

signal = [34;56;12;87;35]

response = [ 33.88;55;11.11;86.77;34.99]

noise = response - signal

rawratio = signal ./ abs(noise)

snr = 10*log10(rawratio)

ans =

   24.5230
   17.4819
   11.2979
   25.7779
   35.4407

This shows that in your observations the signal is in the order of hundreds of times greater than the noise between true and measured response (in the rawratio variable). Signal-to-noise ratio is often (usually) given in decibels (db) which is 10log10(signal/noise)

[cbentter]

But if you only have the signal with the noise?