# Making a Square Wave Gradually

8 visualizzazioni (ultimi 30 giorni)
Cody Gass il 21 Mag 2014
Commentato: Cody Gass il 22 Mag 2014
I made a script where I have a square wave audioplayer made from sine waves based off of
for k = 1:2:order
x = x + (sin(k*2*pi.*f.*t))/k;
y((k+1)/2,:) = x;
pause(.01)
end
where f is an array based off the equation 2^x, and t is another array 0:1/fs:T used for sampling. f is used to select frequencies in an exponential manner so that the pitch goes up linearly. This worked very well, but I wanted to try the same thing but flipped around. The script I'm working on takes a certain frequency and creates a waveform that gradually evolves from a sine wave to a square wave. This is what I have so far:
tic
t = 0:1/fs:T;
timeDomain = 0:1:(fs * T);
y = zeros(size(t * order));
x = zeros(size(t));
h = waitbar(0,'Initializing Fourier Series');
for k = 1:2:order
x = x + (sin(k*2*pi*f.*t))/k;
y(1 + timeDomain + (((k+1)/2)-1)*fs) = x;
if k/order > .05
waitbar(k/order,h,sprintf('Computing Fourier Series %6.2g%%',(100 * k)/order))
end
pause(.01)
end
elapsedTime = toc;
if elapsedTime < 1
waitbar(1,h,sprintf('Playing Square Wave to Order %d after %6.4g seconds',order,elapsedTime))
end
if elapsedTime >= 1
waitbar(1,h,sprintf('Playing Square Wave to Order %d after%6.4g seconds',order,elapsedTime))
end
player = audioplayer(y,fs);
play(player)
pause(T)
close(h)
It seems that most of it is working just fine and dandy, but I'm not getting the full transition. For each k value, the audioplayer plays a one-second section of the wave form and cuts off at T seconds. If there aren't T sections to play, the last section is extended to T. I have no idea why each section is played for precisely one second. I want each section to last T/((order+1)/2) seconds so that each section of the wave form is played equally throughout time T. If anybody could help me out, I'd really appreciate it.
##### 1 CommentoMostra -1 commenti meno recentiNascondi -1 commenti meno recenti
Walter Roberson il 22 Mag 2014
As a debugging step, examine size(y) before the "for k" loop, and also after the "for k" loop. Also give us some sample input parameters to test with.

Accedi per commentare.

### Risposta accettata

Hugo il 22 Mag 2014
Each section is being played for one second because you are setting that in the line
y(1 + timeDomain + (((k+1)/2)-1)*fs) = x;
The key is in the part ((k+1)/2)-1)*fs. When k=1, ((k+1)/2)-1)*fs=0, but when k=3 (which is the next loop in the for statement) ((k+1)/2)-1)*fs=fs. But fs is the number of samples in one second, so the new segment starts one second after the previous one, making the previous one of one second in length.
Notice however that the last segment will have a length equal to T.
To solve this, you should write
y(1 + timeDomain + (((k+1)/2)-1)*fs*T/((order+1)/2)) = x;
This statement will give you a length of T/((order+1)/2) as you requested, but be careful that the number should be an integer.
Just in case, notice that the for loop advances in steps of 2.
Hope this helps.
##### 1 CommentoMostra -1 commenti meno recentiNascondi -1 commenti meno recenti
Cody Gass il 22 Mag 2014
I had a feeling that was what was wrong. The only problem is that it limits my ability to set the order. Is there any way to get around that without rewriting the whole code? If not, I'll use what you've told me. Thank you, I appreciate it.

Accedi per commentare.

### Categorie

Scopri di più su Audio and Video Data in Help Center e File Exchange

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by