Solving the scaling problem.

2 visualizzazioni (ultimi 30 giorni)
Abhilash
Abhilash il 14 Feb 2011
So I have a problem with finding out scaling. I have a vector x1 and a vector x2. I suspect that some elements of x2 might be scaled versions of x1.
I need to see if they are indeed scaled.
so A.x1 = x2, and I need to solve A = x1^-1.x2.
Any ideas how to implement that?

Risposta accettata

Matt Fig
Matt Fig il 14 Feb 2011
If
A = [a 0;0 b] % a and b unknowns
Ax = y % The governing relation between known col vects x and y.
then
A = diag(y./x)

Più risposte (2)

Matt Tearle
Matt Tearle il 14 Feb 2011
If it's just two vectors then you could do
A = x2(1)/x1(1)
norm(A*x1 - x2)
A slightly more generalizable way is
A = x1\x2
norm(A*x1 - x2)
Check to see if the result is on the order of machine roundoff.
  2 Commenti
Doug Hull
Doug Hull il 14 Feb 2011
Abhilash said: "Thanks! I tried that, but it doesn't really solve my purpose.
Here's a link form Wiki...this is actually what I need to implement -
http://en.wikipedia.org/wiki/Eigenvalues_and_eigenvectors#Examples_in_the_plane
Unequal scaling is the one I'm looking at."
Matt Tearle
Matt Tearle il 14 Feb 2011
OK, in that case, Matt Fig's answer is the simplest (A = diag(x2./x1))... but I'm confused by the use of the words "I suspect", "might be", and "if they are indeed scaled". Two vectors will always be related by such an unequal scaling (unless elements of x1 are zero).

Accedi per commentare.


Abhilash
Abhilash il 16 Feb 2011
Thanks guys.
Okay here's what I'm really trying to do. My colleague has these image pairs that will be, in a behavioural experiment, be matched by human subjects as to how similar they think they are (color, shape, use, category etc etc). Before that she wants to do a shape similarity analysis. So what I did was a ratio matching. I imposed the boundary on a "grid" whose "boxes" are 4px by 3 px and for each image, calculated the distance from each point on the boundary within a box to points on the box and took the ratio of those distances of image 1 to 2. I then said, if the ratio lies between 0,9 and 1,1 , give me a 1 in a vector called hit. Summed it up, divided by the length of hit and multiplied by 100 for a percentage.
The trouble is, if I have a unit circle and a circle scaled 0,7 times the unit circle, my algorithm does not show 100% similarity, even though both of them are circles. I want to see if there's a scaling anywhere. Of course, the images are all objects like a screw-driver, an apple, a banana etc.
If I could somehow compensate for scaling, it would help. My idea was then to use this eigenvalue scaling. If the non-zero eigenvalues are all the same, then that is the amount by which that part of the image has been scaled w.r.t to the other image, and hence that part is entirely similar in shape. Then I would just compensate such that in my ratio, I get a 1 at that position.
Makes sense?

Categorie

Scopri di più su Mathematics and Optimization in Help Center e File Exchange

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by