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How do I change the number display from scientific notation to the full number in digits?

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How to make MATLAB output the full number in digits, and not using scientific notation?

Risposta accettata

Oleg Komarov
Oleg Komarov il 6 Ago 2011
format long
or
sprintf('%16.f',2332456943534324)
  9 Commenti
James Upton
James Upton il 16 Lug 2019
Modificato: James Upton il 16 Lug 2019
no matter what number format I display, it still does not show me the full number that was present on the excel file?
Walter Roberson
Walter Roberson il 21 Apr 2020
I believe that those are places where the number stored is not the closest representable number to what the value would round to.

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Più risposte (6)

Image Analyst
Image Analyst il 7 Ago 2011
Modificato: MathWorks Support Team il 8 Nov 2018
To display the maximum number of digits in a variable without using scientific notation, set the output display format to "longG":
format longG
After you set the display format, variables display in decimal notation:
m = rand(1,3)/1000
m =
0.000546881519204984 0.000957506835434298 0.00096488853519927
To avoid displaying scientific notation for variables that exceed 2^50 use "sprintf". For example, this code displays the number 2332456943534324 in decimal notation:
sprintf('%16.f',2332456943534324)
ans =
'2332456943534324'
For more information, see the "format" documentation:
  2 Commenti
Walter Roberson
Walter Roberson il 7 Ago 2011
format long g
helps. However, integers that exceed 2^53 will be represented in scientific notation with "format long g". To get the full digits of those, you need to use sprintf() or fprintf()
Image Analyst
Image Analyst il 7 Ago 2011
Yes it can help. Sometimes some sneak through even with that (if there would be more than three 0's to the right of the decimal point), like this which I tried:
m =
Columns 1 through 4
0.000538342435260057 0.000996134716626886 7.81755287531837e-005 0.000442678269775446
Columns 5 through 8
0.000106652770180584 0.000961898080855054 4.63422413406744e-006 0.000774910464711502

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Kaveh Vejdani
Kaveh Vejdani il 19 Feb 2018
I don't understand why you have accepted the wrong answers. What you're looking for is: format short g
Cheers, Kaveh
  3 Commenti
Kaveh Vejdani
Kaveh Vejdani il 19 Feb 2018
For any formatting, one can find a special case (an absurdly huge number or an infinitesimally small one) to make it fail. For "practical" purposes, long g and short g will do the job perfectly.
Walter Roberson
Walter Roberson il 19 Feb 2018
>> format short g
>> pi
ans =
3.1416
This is not "full number in digits"
>> 1000000
ans =
1e+06
this is not even close to being an "absurdly huge number"
format short g gives you at most 5 significant figures.
format long g gives you at most 15 significant figures. It turns out that is not enough in practice to be unique. There are 24 distinct representable values in unique(pi-37*eps:eps:pi+9*eps), all of which display as 3.14159265358979 under format long g. If the goal is to output enough digits to be able to transfer the values exactly in text form, then format long g is not sufficient.
People get caught by this all the time!
format long g
T = 0.3 - 0.2
T == 0.1
T - 0.1
T =
0.1
ans =
logical
0
ans =
-2.77555756156289e-17
People have difficulty understanding why a value that shows up as 0.1 does not compare as equal to 0.1: the limits of format long g have real effects.

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Mark Bower
Mark Bower il 20 Ott 2017
Modificato: Mark Bower il 20 Ott 2017
A nice, consistent solution is to use "num2str()". The same call works for both display from the command line:
> val = 1234567890
val =
1.234567890000000e+09
> num2str(val)
ans =
1234567890
and also within print statements:
> sprintf(num2str(val))
ans =
1234567890
It also works for floating point numbers:
> val = 123456.789
val =
1.234567890000000e+05
> sprintf(num2str(val))
ans =
123456.789
>
  2 Commenti
Walter Roberson
Walter Roberson il 19 Feb 2018
>> num2str(pi*10^5)
ans =
'314159.2654'
This is not "full decimal places"
Using num2str() inside sprintf() is redundant.
Stephen23
Stephen23 il 20 Feb 2018
Modificato: Stephen23 il 20 Feb 2018
sprintf(num2str(val))
The sprintf is totally superfluous, it does nothing useful at all here, just slows down the code. In any case, using a proper sprintf format string would be quicker than calling num2str, and provide more control over the number of digits, so why not do that?

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Walter Roberson
Walter Roberson il 19 Feb 2018
For MS Windows and Linux, to get full number of digits and not in exponential form, you need to either use the Symbolic toolbox or you need to use a tool such as https://www.mathworks.com/matlabcentral/fileexchange/22239-num2strexact--exact-version-of-num2str- from the File Exchange. This is crucial for MS Windows, which does a rather poor job of converting exact values; Linux does a better job but still has inaccuracies after a while.
On Mac (OS-X, MacOS), the built in conversion is exact, and you can choose to sprintf() with a '%.1074f' format. For example,
>> sprintf('%.1074f', eps(realmin))
ans =
'0.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000004940656458412465441765687928682213723650598026143247644255856825006755072702087518652998363616359923797965646954457177309266567103559397963987747960107818781263007131903114045278458171678489821036887186360569987307230500063874091535649843873124733972731696151400317153853980741262385655911710266585566867681870395603106249319452715914924553293054565444011274801297099995419319894090804165633245247571478690147267801593552386115501348035264934720193790268107107491703332226844753335720832431936092382893458368060106011506169809753078342277318329247904982524730776375927247874656084778203734469699533647017972677717585125660551199131504891101451037862738167250955837389733598993664809941164205702637090279242767544565229087538682506419718265533447265625'
For larger values you might want to trim out trailing zeros from the converted string
val = pi*1E-200;
regexprep( sprintf('%.1074f', val), '0+$', '', 'lineanchors')
ans =
'0.00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000003141592653589793111936498419027683964072757959391149845317813416927695644722162706379483043156554579881967829022575831926635177847590589777088086173081089243142930507159490615800591052996089483276727788901006686618108987452642387169053033459820326372299902201815389727889699071056417123601253516892437642498120285079407325647552658339885701180059456745257476645670329996938769926310811984167666114826593537757304481509915842491117931968666219637406979734598283259283758102504979792257699955371208488941192626953125'

Huw S
Huw S il 31 Gen 2017
If you don't need to know all the decimal points, then do your equation inside round.
saves all the other bother of exponentials.
  1 Commento
Walter Roberson
Walter Roberson il 31 Gen 2017
Unfortunately not the case:
>> format short
>> round(2^54)
ans =
1.8014e+16
>> format long g
>> round(2^54)
ans =
1.8014398509482e+16
>> uint64(2^54)
ans =
uint64
18014398509481984

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Christos Boutsikas
Christos Boutsikas il 21 Apr 2020
You can also use Variable-precision arithmetic via command vpa.
vpa(x) %if x is the output number you are interesting in

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