how to make a vector of 30 rows 1 column with increasing values of elements

I want to make a matrix of 30 rows 1 column like [1;1;1;1;1;2;2;2;2;2;3;3;3;3;3;4;4;4;4;4;5;5;5;5;5;6;6;6;6;6] please anyone help.

Answer 1

[Star Strider]

This works:

V1 = 1:6;
M = repmat(V1', 1, 5)';
V2 = M(:)   % Output Vector

[Zishan]

dear this code is not working

[Zishan]

its working. thanx alot dear :)

[Star Strider]

It does now. I renamed V to V1 after I wrote it, but forgot to update the reference to V1 in the repmat call when I copied it to post it.

[Star Strider]

My pleasure!

[Zishan]

Dear if i want to make vector of 12 rows and 1 column suppose this vector [1;1;1;1;2;2;2;2;2;2;3;3] please tell me code for this.

[Zishan]

please tell me a general code I have to make a larger matrix of almost 3 thousand rows.

[Star Strider]

I do not see a pattern in:

[1;1;1;1;2;2;2;2;2;2;3;3]

so I do not know what to suggest as to how to generate it. If it is random in the length of each value, use the randi function to determine the number of each integer:

Vlen = 10;
V1 = 1:Vlen;
V2 = [];
for k1 = 1:Vlen
    V2 = [V2; k1; repmat(k1, randi(9), 1)];
end

Change Vlen to create the approximate length of the vector you want. If you overshoot, simply truncate it to the length you need.